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3 years ago

Pls help asap due tomorrow

Mathematics

1 answer:

Svet_ta [14]3 years ago

4 0

Based on the information given, it should be noted that the least number of marbles that can be in the bag will be 10 marbles.

<h2>Solution to the probability.</h2>

If the bag contains 60 marbles, the number of red marbles will be:

= 1/5 × 60

= 12 marbles.

The number of white marbles will be:

= 3/10 × 60

= 18 marbles.

The number of blue marbles will be:

= 60 - (12 + 18)

= 60 - 30

= 30 marbles.

Furthermore, when the bag has 4 red marbles and 6 white marbles, there'll be 10 blue marbles.

Lastly, to find the probability of choosing a blue marble, we've to multiply 1/2 by the number given.

Learn more about probability on:

brainly.com/question/25870256

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A box is filled with black (B), white (W), red (R), green (G), and pink (P) phone cases. A phone case is selected at random.

Angelina_Jolie [31]

The Sample Space for the experiment is {B, W, R, G, P}. :) The answer to the second question is 7/12.
Hope this helps!

8 0

3 years ago

Read 2 more answers

Please help me:(***********

jeka94

Answer:

A:

Square

Rectangle

Parallelogram

Quadrilateral

Rhombus

Step-by-step explanation:

All sides and angles are equal so it is a square

All angles are 90 degrees so it is a rectangle (eliminate C)

Opposing angles and side lengths are congruent so it is a parallelogram (eliminate D)

It has 4 sides so it is a quadrilateral (eliminate B)

Since all of the other answers are eliminated you don't necessarily need to prove that is is a rhombus, but it is good practice.

Opposing sides are congruent so it is a rhombus.

4 0

3 years ago

If the parent function f(x) = x^2 is fatter translated 11 units to the left, then translated 5 units down, write the resulting f

nikklg [1K]

The quadratic function given by:

$f(x)=a(x-h)^2+k, \ \ \ a\neq 0$

is in vertex form. The graph of $f$ is a parabola whose axis is the vertical line $x=h$ and whose vertex is the point $(h, k)$ . So:

To translate the graph of a function to the right, left, upward or downward we have:

$For \ a \ positive \ real \ number \ c. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:\\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ g(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ g(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{right}: \\ g(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{left}: \\ g(x)=f(x+c)$

By knowing this things, we can solve our problem as follows:

FIRST.

Translating 11 units to the left:

$g(x)=f(x+11) \\ \\ \therefore g(x)=(x+11)^2$

Then translating 5 units down:

$g(x)=f(x)-c \\ \\ \therefore g(x)=(x+11)^2-5$

Since the new function is fatter, the factor we need to multiply the term $(x+11)^2$ must be less than 1, to make the graph fatter. So, according to our options, there are two factors 1/2 and 2.