All categories

2 years ago

Find the inequality represented by the graph

Mathematics

2 answers:

nlexa [21]2 years ago

7 0

Answer:all you need to do is Times everything

Step-by-step explanation:

EastWind [94]2 years ago

6 0

Answer:

y >= -2x - 5

Step-by-step explanation:

slope = rise / run

slope = -2

y >= -2x - 5

You might be interested in

Please could you find the answers to the questions in the attachment.

Fudgin [204]

( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ )we need 3 equations
1. midpoint equation which is ( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ ) when you have 2 points

2. distance formula which is D= $\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height

so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=( $\frac{11+19}{2} , \frac{10+6}{2}$ )
midpoint=( $\frac{30}{2} , \frac{16}{2}$ )
midpoint= (15,8)

point x=(15,8)

y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=( $\frac{5+21}{2} , \frac{8+0}{2}$ )
midpoint=( $\frac{26}{2} , \frac{8}{2}$ )
midpoint=(13,4)

Y=(13,4)

legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= $\sqrt{(19-11)^{2}+(6-10)^{2}}$
D= $\sqrt{(8)^{2}+(-4)^{2}}$
D= $\sqrt{64+16}$
D= $\sqrt{80}$
D= $4 \sqrt{5}$
BC= $4 \sqrt{5}$

X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= $\sqrt{(13-15)^{2}+(4-8)^{2}}$
D= $\sqrt{(-2)^{2}+(-4)^{2}}$
D= $\sqrt{4+16}$
D= $\sqrt{20}$
D= $2 \sqrt{5}$
XY= $2 \sqrt{5}$

the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC= $4 \sqrt{5}$ and XY= $2 \sqrt{5}$

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= $\sqrt{(21-5)^{2}+(0-8)^{2}}$
D= $\sqrt{(16)^{2}+(-8)^{2}}$
D= $\sqrt{256+64}$
D= $\sqrt{320}$
D= $4 \sqrt{2}$
AD= $4 \sqrt{2}$

so we have
AD= $4 \sqrt{2}$
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
( $4 \sqrt{2}+4 \sqrt{5}$ ) times 1/2 times $2 \sqrt{5}$ =
( $4 \sqrt{2}+4 \sqrt{5}$ ) times \sqrt{5} [/tex] =
$4 \sqrt{10}+4*5$ = $4 \sqrt{10}+20$ =80 $\sqrt{10}$ =252.982

X=(15,8)
Y=(13,4)
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$
Area=80 $\sqrt{10}$ square unit or 252.982 square units

7 0

3 years ago

How many cards he has left

lisabon 2012 [21]

Answer:

Wrong grammar

Step-by-step explanation:

how many cards DOES HE HAVE LEft

3 0

3 years ago

Let X be a random day of the week, coded so that Monday is 1, Tuesday is 2, etc. (so X takes values 1, 2,..., 7, with equal prob

Akimi4 [234]

Answer:

Yes. Have the same distribution.

Step-by-step explanation:

Given that X is a random day of the week, coded so that Monday is 1, Tuesday is 2, etc. (so X takes values 1, 2,..., 7, with equal probabilities).

Y is the next day after X

So Y can be written as X+1

But since highest value is 7, we can write

Y = X+1 mod 7

i.e. whenever X=7, Y= 8= 1 again.

Thus Y can take values as

Y 1 2 3 4 5 6 7

P(Y) = P(X+1) = 1/7

i.e. Y also has the same distribution as X

3 0

3 years ago

Tell whether the statement is always, sometimes, or never true. The LCM of two different prime numbers is their product.

Blizzard [7]

Answer:

Step-by-step explanation:The LCM of two or more prime numbers is equal to their product. ... Assume two prime numbers as two different variables and find their LCM using prime factorization of both the numbers.

3 0

3 years ago

3. F (7,-2). If F is rotated 90 degrees about the origin. What are the<br> coordinates of F?

timama [110]

Well you said the Coordinates of F (7,-2) rotated 90 degrees

7 0

2 years ago