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Snezhnost [94]
2 years ago
12

Slope is - 1/2 and (-3, 2) is on the line.

Mathematics
1 answer:
lions [1.4K]2 years ago
3 0

Answer:

y= -1/2x + 1/2

Step-by-step explanation:

First, use the point-slope formula: y-y1 = m(x-x1)

y-2 = -1/2(x-(-3))

y-2= -1/2x + -1.5

(subtract 2 from both sides)

y = -1/2x + 1/2

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Cart 1 (500 g) moves to the right at 0.40 m/s. Cart 2 (250g) moves to the left at 0.50 m/s. a. If the carts stick after the coll
Dimas [21]

Answer:

after the collision cart 1 will stop and cart 2 will keep moving will 0.1.m/s after stop.

4 0
2 years ago
on halloween kaleb scored 34 pieces of gummi candy. he got 8 times as much sugar candy and 4 times as much chocolate candy. how
Lady bird [3.3K]
We can first find the number of different types of candy he got:

The number of sugar candy he got:

34×8
=272

The number of chocolate candy he got:

34×4
=136

We can then add them all up to find the total pieces of candy he got:

272+136+34
=442

Therefore, the answer is 442.

Hope it helps!
7 0
2 years ago
You should have ____ revolving credit lines. A. 3. B. 1 to 3. C. 2. D. 2 to 6
Rom4ik [11]
Revolving credit lines open account credit offered by banks or other financial institutions.
You should have <span>2 to 6 </span>revolving credit lines.
8 0
3 years ago
Read 2 more answers
Can someone help me with number 3 please??!!
ipn [44]
There are 2 way to solve this.

one using Pythagoras theorem and 2nd using trigonometry

so lets solve it by both

using Pythagoras theorem we know

base^2 + perpendicular^2 = hypotanes^2

6^2 + x^2 = 12^2

36 + x^2 = 144

x^2 = 144- 36 = 108

x = √(108) = √( 2×2×3×3×3)

= (2×3) √ (3) = 6 √3

so answer is option 2

bow lets use trigonometry

we know
sin theta = perpendicular / hypotanes
sin 60 = x /12
x = 12 × sin 60
we kNow sin 60 = √3/ 2
so
x = 12×√3 /2 = 6√3
7 0
3 years ago
I need help with this problem
Arada [10]

Answer:

65.56°

Step-by-step explanation:

We know that if we take dot product of two vectors then it is equal to the product of magnitudes of the vectors and cosine of the angle between them

That is let p and q be any two vectors and A be the angle between them

So, p·q=|p|*|q|*cosA

⇒cosA=\frac{u.v}{|u||v|}

Given u=-8i-3j and v=-8i+8j

|u|=\sqrt{(-8)^{2}+ (-3)^{2}} =8.544

|v|=\sqrt{(-8)^{2}+ (8)^{2}} =11.3137

let A be angle before u and v

therefore, cosA=\frac{u.v}{|u||v|}=\frac{(-8)*(-8)+(-3)*(8)}{8.544*11.3137} =\frac{40}{96.664}

⇒A=arccos(\frac{40}{96.664} )=arccos(0.4138 )=65.56

Therefore angle between u and v is 65.56°

5 0
2 years ago
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