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OverLord2011 [107]
3 years ago
10

1. How many feet long is the space Mr. Hamilton wants to fill with pictures? Explain how you know

Mathematics
2 answers:
mihalych1998 [28]3 years ago
6 0

Answer:

4 feet I think

Step-by-step explanation:

Ipatiy [6.2K]3 years ago
6 0
8 pictures can fit on the wall, the person that said 4 is correct for a part. (Correct me if I’m wrong but I’m sure I’m not!)
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D 0.62

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A researcher compares the effectiveness of two different instructional methods for teaching physiology. A sample of 178 students
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Answer:

critical value = 1.645

The 90% confidence interval = ( -22.62, -17.58)

Step-by-step explanation:

Given that:

the sample  size n_1 = 178

the sample size n_2 = 226

the sample mean \overline x_1 = 54.4

the sample mean \overline x_2 = 74.5

population standard deviation \sigma_1 = 18.58

population standard deviation \sigma_2 = 9.52

level of significance ∝ = 1 - 0.90 = 0.10

The critical value for Z_{\alpha/2} = Z _{0.10/2} = Z_{0.005} is 1.645

For the construction of our confidence interval, we use 90% since that is used to find the critical value.

∴

The margin of error = Z \times\sqrt{\dfrac{\sigma_1^2}{n_1} + \dfrac{\sigma_2^2}{n_2}}

1.645 \times\sqrt{\dfrac{18.58^2}{178} + \dfrac{9.52^2}{226}}

1.645 \times\sqrt{\dfrac{345.2164}{178} + \dfrac{90.6304}{226}}

1.645 \times\sqrt{2.34042}

\simeq 2.52

The lower limit = ( \overline x_1 - \overline x_2) - (M.O.E)

= ( 54.4-74.5) - (2.52)

= -20.1 - 2.52

= -22.62

The upper limit = ( \overline x_1 - \overline x_2) + (M.O.E)

= ( 54.4-74.5) + (2.52)

= -20.1 + 2.52

= -17.58

The 90% confidence interval = ( -22.62, -17.58)

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