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nordsb [41]
2 years ago
6

During a drought, the water level in a reservoir dropped 3 in. each week for 5 straight weeks. Express the overall change in wat

er level as a signed number.​
Mathematics
1 answer:
aliina [53]2 years ago
6 0

Answer:

v = -3w

Step-by-step explanation:

water level/volume = -3 x weeks

v = -3w

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Find X FIND Y<br> PlEase Help me
baherus [9]

The X and Y angles created by lines intersection in the pictures are 18° and 54°.

Based on the picture, angle ∠MON is a right angle hence it has an 90° angle. We then know that the ∠MOA is 72°. Because angle ∠MOA lies within the angle ∠MON, hence we can write the following formula:

∠MON = ∠MOA +∠AON = 90°

∠MON = 72° + ∠AON = 90°

∠AON = 18° ... (i)

If we focus on the line CD being intersected by the line AB, hence we can conclude that the angles form by this intersection will follow these rules:

∠AOD = ∠BOC

∠AOC = ∠BOD

∠AOD + AOC = 180°

∠BOC + ∠BOD = 180°

Based on the picture, we know that:

∠BOC = x

∠AOC = ∠MOA + ∠MOC

∠AOC = 72° + y ...(ii)

∠AOD = ∠AON + ∠NOD

∠AOD = 18° +2x

∠BOC = 3x ... (iii)

Because we already know that ∠BOC = AOD, hence we could rewrite the formula into:

∠BOC = ∠AOD

3x = 18° + 2x

x = 18° ... (iv)

To find the value of y, we need to focus on angle ∠AOC. Based on the previous calculations and formulas, we  know that:

∠AOC + ∠BOC = 180° ... (v)

Input equations (ii) and (iv) into (v)

∠AOC + ∠BOC = 180°

(72° + y) + 3x = 180°

72° + y + 3(18°) = 180°

126° + y = 180°

y = 54° ... (vi)

Learn more about the angles by lines intersection here: brainly.com/question/2077876?referrer=searchResults

#SPJ1

4 0
1 year ago
Find the indefinite integral. (Note: Solve by the simplest method—not all require integration by parts. Use C for the constant o
umka2103 [35]

Answer:

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-1/2  ln⁡(1+x^2 )+C

Step-by-step explanation:

∫▒〖1st .2nd dx=1st∫▒〖2nd dx〗-∫▒〖(derivative of 1st) dx∫▒〖2nd dx〗〗〗

Let 1st=arctan⁡(x)

And 2nd=1

∫▒〖arctan⁡(x).1 dx=arctan⁡(x) ∫▒〖1 dx〗-∫▒〖(derivative of arctan(x))dx∫▒〖1 dx〗〗〗

As we know that  

derivative of arctan(x)=1/(1+x^2 )

∫▒〖1 dx〗=x

So  

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-∫▒〖(1/(1+x^2 ))dx.x〗…………Eq1

Let’s solve ∫▒(1/(1+x^2 ))dx by substitution now  

Let 1+x^2=u

du=2xdx

Multiply and divide ∫▒〖(1/(1+x^2 ))dx.x〗 by 2 we get

1/2 ∫▒〖(2/(1+x^2 ))dx.x〗=1/2 ∫▒(2xdx/u)  

1/2 ∫▒(2xdx/u) =1/2 ∫▒(du/u)  

1/2 ∫▒(2xdx/u) =1/2  ln⁡(u)+C

1/2 ∫▒(2xdx/u) =1/2  ln⁡(1+x^2 )+C

Putting values in Eq1 we get

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-1/2  ln⁡(1+x^2 )+C  (required soultion)

3 0
3 years ago
Read 2 more answers
Hi :) I'm working with rational and irrational numbers. There's a problem .025 with the 25 repeating. If anyone could lend some
sp2606 [1]
1/40 would be your answer because 0.025 is would be 25/1000. Simplify that then you would get 1/40.
8 0
3 years ago
PLEASE HELP ME PLEAESESES
Bogdan [553]

Answer:

Make a coordinate plane and you have to solve around the orgin say 4,4 and 4,1

Step-by-step explanation:

8 0
3 years ago
The probability of rolling a 5 on a six-sided number cube is 1/6. What is the probability of not rolling a 5 on a six-
Nezavi [6.7K]

Answer:

Step-by-step explanation:

Event of not rolling a 5= {1,2,3,4,6}

P(not rolling a 5) = 5/6

5 0
3 years ago
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