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Dominik [7]
3 years ago
11

Can you plz help out​

Mathematics
1 answer:
saul85 [17]3 years ago
7 0
<h3>Answer: Choice D</h3>

Work Shown:

r = 6 = radius

h = 9 = height

V = \text{volume of cylinder}\\\\V = \pi*r^2*h\\\\V = \pi*6^2*9\\\\V = \pi*36*9\\\\V = \pi*324\\\\V = 324\pi\\\\

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Which is the direct linear variation equation for the relationship?
Step2247 [10]
Y varies as x
y=kx
y=12 when x=4
12=k4
divide 4
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answer is B
6 0
3 years ago
If quadrilateral ABCD rotates 90° counterclockwise about the origin, what are the coordinates of A′ in quadrilateral A′B′C′D′ ?
Vesna [10]

Answer:

Option B is correct.

The coordinate of A' is (-2 , -1)

Explanation:

The coordinates of ABCD are A = (-1,2) , B(1,1) , C =(1,-1) and D(-2,-2).

Rotation means moving the shape  around a fixed point clockwise or anticlockwise, and by a certain number of degrees.

Rule for 90° counterclockwise rotation about the origin: (x,y) \rightarrow (-y,x)

or we can say that switch x and y in the coordinates and make y value opposite.

Then, the coordinate of A' :

A(-1,2) \rightarrow A'(-2 ,-1)

Therefore, the coordinate of A' in the quadrilateral A'B'C'D' is, (-2 ,-1)


6 0
4 years ago
Read 2 more answers
Mark is proving the Pythagorean Theorem. He drams right triangle KL with altitude JM First he proves JKLAMK) and JKL-MIL ssing t
Troyanec [42]

Answer:

a)

Step-by-step explanation:

<u>Given:  Step 3</u>

(JK)² = LK · MK  and  (LJ)² = LK · ML

<u>Step 4</u>

Addition property of equality

(JK)² + (LJ)² = LK · MK + LK · ML

<u>Step 5</u>

Distributive property

(JK)² + (LJ)² = LK (MK + ML)

3 0
2 years ago
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The scale on a map is 1cm = 250 km. What would be the distance on the map, if the actual distance between the two cities is 1,00
xz_007 [3.2K]

Answer:

so if its actually 1000 and that map thing is 250

250 goes into 1000 4 times so

4cm

Hope This Helps!!!

5 0
3 years ago
Read 2 more answers
U
Oxana [17]

Answer:

Step-by-step explanation:

a(n) = a1 *(1.25)^{(n-1)}

a(1) = 5

a(2) = 5*(1.25)^{(2-1)}\\a(2) = 5*(1.25)^{1}\\a(2) = 5*(1.25)\\a(2) = 6.25

a(3) = 5 * (1.25)^{(3-1)} \\a(3) = 5 * (1.25)^{2}\\a(3) = 5 * 1.565\\a(3) = 7.813

a(4) = 5* (1.25)^{(4-1)}\\ a(4) = 5* (1.25)^{3}\\a(4) = 5* 1.953\\a(4) = 9.766

a(5) = 5 * (1.25)^{(5-1)}\\a(5) = 5 * (1.25)^{4}\\a(5) = 5 * 2.441\\a(5) = 12.207

a(6) = 5 * (1.25)^{5}\\a(6) = 5 * 3.052\\a(6) = 5 * 3.0517\\a(6) = 15.259

a(1) = 5

a(2) = 6.25

a(3) = 7.813

a(4) = 9.766

a(5)=12.207

a(6)=15.259

3 0
3 years ago
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