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steposvetlana [31]
3 years ago
10

If quadrilateral ABCD rotates 90° counterclockwise about the origin, what are the coordinates of A′ in quadrilateral A′B′C′D′ ?

Mathematics
2 answers:
Vesna [10]3 years ago
6 0

Answer:

Option B is correct.

The coordinate of A' is (-2 , -1)

Explanation:

The coordinates of ABCD are A = (-1,2) , B(1,1) , C =(1,-1) and D(-2,-2).

Rotation means moving the shape  around a fixed point clockwise or anticlockwise, and by a certain number of degrees.

Rule for 90° counterclockwise rotation about the origin: (x,y) \rightarrow (-y,x)

or we can say that switch x and y in the coordinates and make y value opposite.

Then, the coordinate of A' :

A(-1,2) \rightarrow A'(-2 ,-1)

Therefore, the coordinate of A' in the quadrilateral A'B'C'D' is, (-2 ,-1)


Greeley [361]3 years ago
4 0

I believe the answer is (-2,-1)   after the original point (2,1) goes through the change of -y,x

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What does a irrational number look like
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A irrational number is a number that can't be expressed as a ratio of two whole numbers. That's it.

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1 is a rational number because it is 1/1

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2.333... (infinite number of digits, all equal to three) is rational because it is equal to 7/3.

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pi is irrational. This is much more complicated and is a result from 19th century.

As you see, there is absolutely no mention of the digits in the definition or in the proofs I presented.

Now the result that you probably hear about and wanted to remember (slightly incorrectly) is that a number is rational if and only if its decimal expansion is eventually periodic. What does it mean ?

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