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2 years ago

Help me out plssszzszzszz

Mathematics

1 answer:

AveGali [126]2 years ago

8 0

Answer:

$the \: answer \: is \: \\ y - 7 = 1(x - 4) \\ y - 7 = x - 4 \\ or \: in \: other \: way \: \\ y = x+ 3$

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2 years ago

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3 years ago

Which expression is equivalent to \frac{10q^5w^7}{2w^3}.\ \frac{4\left(q6\right)^2}{w^{-5}} for all values of q and w where the

mestny [16]

Answer:

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9$

Step-by-step explanation:

Given

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

Required

Determine the equivalent expression

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

Simplify the first fraction

$\frac{5q^5w^7}{w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

Apply law of indices on the first fraction;

$5q^5w^{7-3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

$5q^5w^4.\ \frac{4\left(q^6\right)^2}{w^{-5}}$

$\ \frac{5q^5w^4*4\left(q^6\right)^2}{w^{-5}}$

Apply law of indices:

$5q^5w^4*4\left(q^6\right)^2 * w^{5}$

Evaluate the bracket

$5q^5w^4*4 * q^{12} * w^{5}$

Collect Like Terms

$5*4q^5* q^{12}*w^4 * w^{5}$

$20q^5* q^{12}*w^4 * w^{5}$

$20q^{5+12}*w^{4+5}$

$20q^{17}w^9$

Hence:

$\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}} =20q^{17}w^9$

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3 years ago

Find the solution set of the inequality

Kobotan [32]

Step-by-step explanation:

$= > x - \frac{4}{5} \leqslant \frac{1}{5}$

$= > x \leqslant \frac{1}{5} + \frac{4}{5}$

$= > x \leqslant 1$

=> Solution in the set {-2,-1,0,1,2} is {-2,-1,0,1}

Hope you've understood the solution.

8 0

2 years ago