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lina2011 [118]
3 years ago
7

Math pls help!! larger number? smaller number?

Mathematics
1 answer:
Georgia [21]3 years ago
5 0

Answer:

larger number  = 35

smaller number = 26

Step-by-step explanation:

let larger number be x

and another ( x-9 )

so, x+x-9=61

2x = 70

x = 35

smaller number = 35 - 9

= 26

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108 because the full measurements is 180

Step-by-step explanation:

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If 3×1=34 2×3=65 6×1=67 5×4=209 then 6×3=
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189.

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4 years ago
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5(y-4)=7(2y+1)<br>I need the answer​
8_murik_8 [283]

Answer: y = -3

Move all terms containing y to the left, all other terms to the right

<u>Add -14y to each side of the equation</u>

<u></u>-20 + 5y + -14y = 7 + 14y + -14y<u></u>

<u></u>

<u>Combine like terms: 5y + -14y = -9y </u>

<u></u>-20 + -9y = 7 + 14y + -14y<u></u>

<u></u>

<u>Combine like terms: 14y + -14y = 0 </u>

<u></u>-20 + -9y = 7 + 0\\-20 + -9y = 7<u></u>

<u></u>

<u>Add '20' to each side of the equation</u>

<u></u>-20 + 20 + -9y = 7 + 20<u></u>

<u></u>

<u>Combine like terms: -20 + 20 = 0 </u>

<u></u>0 + -9y = 7 + 20\\-9y = 7 + 20<u></u>

<u></u>

<u>Combine like terms: 7 + 20 = 27 </u>

<u></u>-9y = 27<u></u>

<u></u>

<u>Divide each side by -9</u>

<u></u>-9y/9=27/-9\\y=-3<u></u>

8 0
3 years ago
Not all visitors to a certain company's website are customers. In fact, the website administrator estimates that about 5% of all
Gnom [1K]

Answer:

0.0135 = 1.35% probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

Step-by-step explanation:

For each visitor of the website, there are only two possible outcomes. Either they are looking for the website, or they are not. The probability of a customer being looking for the website is independent of other customers. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

5% of all visitors to the website are looking for other websites.

So 100 - 5 = 95% are looking for the website, which means that p = 0.95

Find the probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

This is P(X = 2) when n = 4. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = x) = C_{4,2}.(0.95)^{2}.(0.05)^{2} = 0.0135

0.0135 = 1.35% probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

5 0
2 years ago
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