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2 years ago

I don’t understand how to set up the equation and expressions, I pretty much need help with everything

Mathematics

2 answers:

Veseljchak [2.6K]2 years ago

6 0

idk sorry :(((((((((((((((((((((((((((((((((((((((((((

Alexus [3.1K]2 years ago

5 0

cats: 2t

fish: 5t

16= 2t + 5t + t

dogs: 2, cats: 4, fish: 10

so if Amy has 2 dogs, she would have 4 cats (twice as many dogs) and 10 fish (5 times as many dogs).

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Help please! I don't get this.

slava [35]

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2 years ago

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What is 16 to 29 and 15 in at ratio

Semmy [17]

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2 years ago

The principal of the school is looking over grade reports, specifically scores on math quizzes.

guapka [62]

Answer:

Range = 45

Median = 75

Step-by-step explanation:

Based on the attached box and whisker plot :

From the plot :

Maximum value = 95

Minimum value = 50

The median value can be obtained from the box and whisker plot. The median value from the plot is ; the green dotted point inside the box :

This point is marked 75.

Hence, median value = 75

Range = maximum - minimum

Range =. 95 - 50 = 45

8 0

3 years ago

The students in Mr. Wilson's Physics class are making golf ball catapults. The

Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is $0 \leq x \leq 48.6\ ft$ and the range is $0 \leq y \leq 8.3\ ft$

Step-by-step explanation:

we have

$y=-0.014x^{2} +0.68x$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's distance from the catapult in feet

y is the flight of the balls in feet

Part a) How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-0.014x^{2} +0.68x=0$

$a=-0.014\\b=0.68\\c=0$

substitute in the formula

$x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}$

$x=\frac{-0.68(+/-)0.68} {(-0.028)}$

$x=\frac{-0.68(+)0.68} {(-0.028)}=0$

$x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft$

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

$y=-0.014x^{2} +0.68x$

Find out the derivative and equate to zero

$0=-0.028x +0.68$

Solve for x

$0.028x=0.68$

$x=24.3$

<em>Alternative method</em>

To determine the x-coordinate of the vertex, find out the midpoint between the x-intercepts

$x=(0+48.6)/2=24.3\ ft$

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

$y=-0.014(24.3)^{2} +0.68(24.3)$

$y=8.3\ ft$

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A reasonable domain is the distance between the two x-intercepts

$0 \leq x \leq 48.6\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

we have the interval -----> [0,8.3]

$0 \leq y \leq 8.3\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

8 0

2 years ago

Highlight EVERY coordinate ratio in the table below in purple

mel-nik [20]

Answer:

Step-by-step explanation:

You already highlighted the term coordinate ratio in purple.

8 0

3 years ago