After 5 throws in a game of darts, Brent's mean score was 32. Calculate his total score.

1 answer:

5 0

1.To know this answer, we need to know some vocabulary that's used in t. Most people don't know how to solve questions if they have hard Vocabulary and what the question is Asking

Mean=The average of all his throws

It's asking us to calculate his total score

2. Find Clues to help you solve word problems

Finding clues in Word Problems is a very important part a lot of people skip but this helps you solve the question easier

5 throws and Mean Score is 32 are the clues

3. Guess and check

The method to this thingy is called guess and check. There is another method which is slightly harder and i just don't want to do it.

Let's just say his scores were... 5, 6, 4, 5,10Add them up and you get 30Then 30/5

Let's try bigger numbers

20+25+20+20

If you like this method, you may try it another method is called work Backwards

5x32=160

Then divide 160 by 5 to double check and you get 32!!

========================================

Therefore, the answer s 160 as his total score

hope this gives you a clue to what we are doing and when you have a question like this, I really hope you understand the concept

Hope this helped (:

You might be interested in

2) The box-and-whisker plot below represents the math test scores of 20 students.

Irina18 [472]

can you provide pictures of the plot?

3 0

3 years ago

Shawn said that in standard notation,

insens350 [35]

Answer:

Shawn is incorrect.

Step-by-step explanation:

The decimal is moving 7 places to the right. The 2 is the third digit, so there will be 4 0s after it.

3 0

3 years ago

In this problem, x = c1 cos t + c2 sin t is a two-parameter family of solutions of the second-order de x'' + x = 0. find a solut

nordsb [41]

If you are already given the general solution, finding the particular solution means to impose some conditions in order to fix the coefficients of the general solution.

The first thing we need to impose is that the function must output -1 when the input is zero. So, if we plug zero as input we have

$x(t) = c_1 \cos(t) + c_2 \sin(t) \implies x(0) = c_1 \cos(0) + c_2 \sin(0) = c_1$

But we want $x(0)=-1$ , which implies $x(0)=c_1=-1$

So, we fixed the first coefficient. To fix the second one, we can use the second piece of information (and of course the already-found value for $c_1$ ).