Question

A constant force F=6i+8j?6k moves an object along a straight line from point (6, 0, -10) to point (-6, 7, 2).

Answer 1

Answer:

The work done is 56 joules.

Step-by-step explanation:

The work done by a force is defined to be the product of the component of the force along $\vec{D}$ and the distance moved:

$W=\vec{F}\cdot \vec{D}$

For our case the displacement vector is

$\vec{D}=\langle -6,7,2\rangle- \langle 6,0,-10\rangle\\\vec{D}=\langle -12,7,12\rangle$

And the work done is

$W=\langle 6,8,6\rangle \cdot\langle -12,7,12\rangle\\W=6\left(-12\right)+8\cdot \:7+6\cdot \:12\\W=56$

If the unit of length is meters and the magnitude of the force is measured in newtons,then the work done is 56 joules.