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2 years ago

The diameter of a circle is 6 meters. What is the circle's circumference?

Mathematics

1 answer:

Alinara [238K]2 years ago

8 0

Answer:

C = 6 pi cm or approximately 18.84 cm

Step-by-step explanation:

The circumference of a circle is given by

C = pi * d

C = 6 pi

If we approximate pi by 3.14

C = 6 * 3.14

C =18.84

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3 years ago

Alvin is 7 years younger than Elgas. The sum of their ages is 63. What is Elgas age?

Elden [556K]

Answer:

Elgas is 35.

Step-by-step explanation:

Let's set up an equation.

Alvin is 7 years younger than Elgas.

A = E - 7

The sum of their ages is 63.

A + E = 63

Let's use substitution.

Plug in the first equation of A into the second equation.

A + E = 63

(E - 7) + E = 63

Combine like terms.

2E - 7 = 63

Add 7 to both sides.

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Divide both sides by 2.

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Elgas is 35.

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6 0

3 years ago

What is X-5+10x+3???

Alekssandra [29.7K]

Answer:

-2+11x

Step-by-step explanation:

Combine like terms

(-5+3)+(x+10x)

-5+3 = -2

x+10x = 11x

-2+11x

8 0

3 years ago

LCM of x<sup>2</sup>+5x+6 and x<sup>2</sup>-x-6 is ………………………

sergejj [24]

Answer:

$(x^2 - 9)(x + 2)$

Step-by-step explanation:

Given:

$x^2 + 5x + 6$

$x^2 - x - 6$

Required:

LCM of the polynomials

SOLUTION:

Step 1: Factorise each polynomial

$x^2 + 5x + 6$

$x^2 + 3x + 2x + 6$

$(x^2 + 3x) + (2x + 6)$

$x(x + 3) + 2(x + 3)$

$(x + 2)(x + 3)$

$x^2 - x - 6$

$x^2 - 3x +2x - 6$

$x(x - 3) + 2(x - 3)$

$(x + 2)(x - 3)$

Step 2: find the product of each factor that is common in both polynomials.

We have the following,

$x^2 + 5x + 6 = (x + 2)(x + 3)$

$x^2 - x - 6 = (x + 2)(x - 3)$

The common factors would be: =>

$(x + 2)$ (this is common in both polynomials, so we would take just one of them as a factor.

$(x + 3)$ and,

$(x - 3)$

Their product = $(x - 3)(x + 3)(x +2) = (x^2 - 9)(x + 2)$

4 0

4 years ago

Which of the following are identities? Check all that apply

Natasha2012 [34]

Answer:

A, C

Step-by-step explanation:

Actually, those questions require us to develop those equations to derive into trigonometrical equations so that we can unveil them or not. Doing it only two alternatives, the other ones will not result in Trigonometrical Identities.

Examining

A) True

$\frac{1-tan^{2}x}{2tanx} =\frac{1}{tan2x} \\ \frac{1-tan^{2}x}{2tanx} =\frac{1}{\frac{2tanx}{1-tan^{2}x}}\\ tan2x=\frac{1-tan^{2}x}{2tanx}$

Double angle $tan2\alpha =\frac{1 -tan^{2}\alpha }{2tan\alpha}$

B) False,

No further development towards a Trig Identity

C) True

Double Angle Sine Formula $sin2\alpha =2sin\alpha *cos\alpha$

$sin(8x)=2sin(4x)cos(4x)\\2sin(4x)cos(4x)=2sin(4x)cos(4x)$

D) False No further development towards a Trig Identity

$[sin(x)-cos(x)]^{2} =1+sin(2x)\\ sin^{2} (x)-2sin(x)cos(x)+cos^{2}x=1+2sinxcosx\\ \\sin^{2} (x)+cos^{2}x=1+4sin(x)cos(x)$

7 0

3 years ago

Read 2 more answers