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ratelena [41]
3 years ago
8

Part 1 of 2

Mathematics
1 answer:
raketka [301]3 years ago
4 0

Answer:

The coach ticket she bought was =$142 and the

The first ticket was =$1002

That is so the amount of coach ticket she bought was 1560 and the first class ticket is 11880

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Whats the answer for this
Oxana [17]

Answer:

a) Angle X = 108°

<h3>C). Vertically opposite angles</h3>

as AD is parallel to EH both the angles are equal

7 0
2 years ago
Read 2 more answers
If a data value is 2 and the mean is 11, what is the associated<br> deviation?
Westkost [7]

Answer:

the mean = 9, and the mean deviation = 3.75

Hope this helps! :)

3 0
2 years ago
What is the equation of the following line? Be sure to scroll down first to see all answer options.
Annette [7]
From the figure the given line passes through the points (0, 0) and (-4, 8).

Recall that the equation of a straight line is given by
\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1}

Thus, The equation of the given figure is given by
\frac{y-0}{x-0} = \frac{8-0}{-4-0}= \frac{8}{-4}  \\  \\ -4y=8x \\  \\ y=-2x
8 0
3 years ago
Please help i don’t understand this
swat32

Similar polygons only differ by a scaling factor. In other words, two polygons are similar if one is the scaled version of the other.

In particular, this implies that the angles are preserved, and the correspondent sides are in proportion.

These two polygons are both rectangles, so the angles are preserved. We must check the sides, and we have to check if the smaller sides are in the same proportion as the bigger sides.

So, the two rectangles are similar if the following is true.

4\div 5 = 11\div 12

In any proportion, the product of the inner terms must be the same as the product of the outer terms:

4\cdot 12 = 5\cdot 11 \iff 48=55

This is clearly false, and thus the two rectangles are not similar.

5 0
3 years ago
The formula for finding the area of a circle is A=pi r 2.Solve the formula for r
olga55 [171]

Answer:

See Explanation

Step-by-step explanation:

A = \pi {r}^{2}  \\  \\  \frac{A}{\pi}  =  {r}^{2}  \\  \\ \huge \red{ \boxed{ r =  \sqrt{\frac{A}{\pi}  } }}

3 0
4 years ago
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