HELP PLEASE ASAP! 12 points

1.6x 10^5 in standard notation.

Gekata [30.6K]

The answer is 160,000. Since it's positive,move the decimal point 5 times to the right.

ANSWER: 160,000

3 0

3 years ago

G(x)=2x-8, f(x)=5-g(x) what is the value of f(10)

Rudik [331]

By evaluating the function, we conclude that f(10) = -7

<h3>How to evaluate the function f(x)?</h3>

Here we know that:

g(x) = 2x - 8

And f(x) = 5 - g(x).

Then we can write:

f(x) = 5 - (2x - 8) = 5 - 2x + 8 = -2x + 13

Now we want ot evaluate it in x = 10, this means replace the variable by the number 10.

f(10) = -2*10 + 13 = -20 + 13 = -7

Then, we conclude that f(10) = 7

If you want to learn more about evaluating:

brainly.com/question/1719822

#SPJ1

5 0

1 year ago

Find the slope of the graphed line

Contact [7]

Answer:

slope = 3/5

Step-by-step explanation:

slope = rise/run = 3/5

or (longer way w/ the points)

slope = (y2-y1)/(x2-x1) = (5-2)/(4-(-1)) = 3/5

3 0

2 years ago

Evaluate the function for the given values to determine if the value is a root. p(−2) = p(2) = The value is a root of p(x).

bija089 [108]

Note: Since you missed to mention the the expression of the function $p(x)$ . After a little research, I was able to find the complete question. So, I am assuming the expression as $p(x)=x^4-9x^2-4x+12$ and will solve the question based on this assumption expression of $p(x)$ , which anyways would solve your query.

Answer:

As

$p\left(-2\right)=0$

Therefore, $x=-2$ is a root of the polynomial $p(x)=x^4-9x^2-4x+12$

As

$p\left(2\right)=-16$

Therefore, $x=2$ is not a root of the polynomial $p(x)=x^4-9x^2-4x+12$

Step-by-step explanation:

As we know that for any polynomial let say $p(x)$ , $c$ is the root of the polynomial if $p(c)=0$ .

In order to find which of the given values will be a root of the polynomial, $p(x)=x^4-9x^2-4x+12$ , we must have to evaluate $p(x)$ for each of these values to determine if the output of the function gets zero.

So,

Solving for $p\left(-2\right)$