The rate of the wind is given to be 210 the rate of the plane in mid air is given as 830
<h3>Howe to solve for the rate of the plane and wind</h3>
In 7 hours the kilometer traveled = 4340
P + W = 4340/7
= 620
P-W = 3120/3 hours
= 1040
2p = 1040 + 620
= 1660
p =830
W = 1040 - 830
= 210
Hence the rate of the wind is given to be 210 the rate of the plane in mid air is given as 830
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This should be simple, add the Amounts of snow for the first week
4.32 + 6.86 = 11.18
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The subtract the amounts of snow from each week
11.18 - 7.89 = 3.29
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C.) 3.29 is your answer
Answer:
area= 1/2*(h*b) h- height, b- base
the triangle is isosceles (denoted by the 2 dashes on the sides of the triangle)
so they are equal in length
angles in triangle = 180
so 38+38=76
180-76=104
base=24
divide the triangle in the center
so now triangle 1(left) the base = 12
and triangle 2(right) the base = 12
use trigonometric ratios
in this we need to find the height
which is opposite of 38,
we already have the adjacent =12
so the ratio is Tan (Tangent Opposite/Adjacent)(TOA)
Tan38= (12/h)
multiply by h
h*Tan38=12
h=12/tan38 = 15.35929959
Use calculator it’s just square roots
First do .80 x 10 to get $8 then add 8 to 5.50 to get $13.50
