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Elodia [21]
2 years ago
7

When calculating a loan’s effective rate, if the interest compounds every two months, what value of n do you plug into your eq

uation? a. 2 b. 0. 167 c. 6 d. 60.
Mathematics
1 answer:
Andrej [43]2 years ago
8 0

The loan's effective rate and interest compound every two months then the value of n would be 6.

Given that,

When calculating a loan's effective rate, the interest compounds every two months.

We have to determine,

What value of n do you plug into your equation?

According to the question,

The calculation of compounded interest would be derived with the following formula:

\rm P = \left (1+\dfrac{r}{n}\right)^{nt}\\\\

In a year there are 12 months and when the interest rate is said to be compounded every two months then it implies that the number of months would be 6 months.

Then,

The value of n is,

\rm 2n = 12\\\\n = \dfrac{12}{6}\\\\n = 6

Hence, The loan's effective rate and interest compounds every two months then the value of n would be 6.

For more details, about Interest Rate refers to the link given below.

brainly.com/question/7967946

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hram777 [196]

Answer:

4/3

Step-by-step explanation:

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7 0
3 years ago
Convert a markup of 15% on selling price to its equivalent markup on cost.
spayn [35]

Answer:

option: D is correct. (  (D) a markup of 15% on selling price is equivalent to a 85% markup on cost ).

Step-by-step explanation:

" Markup is the percentage difference between a product's cost and its selling price "

Since we are asked to Convert a markup of 15% on selling price to its equivalent markup on cost.

As there is a markup of  15% on selling price. Hence the cost of the product would be (100-15)%=85% of the selling price.

<em>Hence, a markup of 15% on selling price is equivalent to a 85% markup on cost.</em>

<em>Hence, option D is true.</em>

5 0
4 years ago
solve for each please i really need help if u want to help me with my test and i get an a or a b i will give u 500 dollars
Len [333]

Answer:

The relation is not a function

The domain is {1, 2, 3}

The range is {3, 4, 5}

Step-by-step explanation:

A relation of a set of ordered pairs x and y is a function if

  • Every x has only one value of y
  • x appears once in ordered pairs

<u><em>Examples:</em></u>

  • The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)
  • The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)
  • The domain is the set of values of x
  • The range is the set of values of y

Let us solve the question

∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}

∵ x = 1 has y = 3

∵ x = 2 has y = 3

∵ x = 3 has y = 4

∵ x = 2 has y = 5

→ One x appears twice in the ordered pairs

∵ x = 2 has y = 3 and 5

∴ The relation is not a function because one x has two values of y

∵ The domain is the set of values of x

∴ The domain = {1, 2, 3}

∵ The range is the set of values of y

∴ The range = {3, 4, 5}

3 0
3 years ago
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The slope is rise/run.

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The rise is 3.

The difference in x-values is the run. 4-0=4  0-(-4) = 4

The run is 4

Rise/run = 3/4  That is the slope.

8 0
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8×(30+2)=(8×_)+(8×2)
irinina [24]
Using the distributive property, a(b+ c) = ab + ac. In this case, b is 30, so the blank is 30.
6 0
4 years ago
Read 2 more answers
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