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Alecsey [184]
2 years ago
12

Which part of the computer is responsible for managing memory allocation for all applications

Computers and Technology
1 answer:
vovikov84 [41]2 years ago
7 0

Answer:

Option B

Explanation:

The operating system is the type of software that is responsible for managing the processor time and also the memory allocation in the system. The operating system mainldeals with the processor time by scheduling the processor work done in the system.

The OS mainly controls the system and then schedule the execution of various types of function by the central processing unit (CPU). It also controls the memory allocation in the system.

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For which of the four game elements will you give a detailed description about the challenges that the player will face, such as
vaieri [72.5K]

The four game elements that will give you  a detailed description about the challenges that the player will face is option D: objective.

<h3>What goals does game development have?</h3>

To bring about creativity and originality in task completion and issue solving. to prepare pupils for group collaboration.

Note that giving the player a clear objective gives them something to aim for. Make sure the player can relate to this motivation.

Therefore, The most crucial component of a game can be its objectives, which determine how the game is won or lost, what the player is instructed to perform in-game, and what the player must do to gain optional <em>Achievements</em>.

Learn more about objective from

brainly.com/question/18516671
#SPJ1

3 0
1 year ago
⦁ Consider transferring an enormous file of L bytes from Host A to Host B. Assume an MSS of 536 bytes. ⦁ What is the maximum val
timurjin [86]

Answer:

a)  There are approximately  2^32 = 4,294,967,296 possible number of the sequence. This number of the sequence does not increase by one with every number of sequences but by byte number of data transferred. Therefore, the MSS size is insignificant. Thus, it can be inferred that the maximum L value is representable by 2^32 ≈ 4.19 Gbytes.

b)  ceil(2^32 / 536) = 8,012,999

The segment number is 66 bytes of header joined to every segment to get a cumulative sum of 528,857,934 bytes of header. Therefore, overall number of bytes sent will be 2^32 + 528,857,934 =  4.824 × 10^9 bytes.  Thus, we can conclude that the total time taken to send the file will be 249 seconds over a 155~Mbps link.

Explanation:

a)  There are approximately  2^32 = 4,294,967,296 possible number of the sequence. This number of the sequence does not increase by one with every number of sequences but by byte number of data transferred. Therefore, the MSS size is insignificant. Thus, it can be inferred that the maximum L value is representable by 2^32 ≈ 4.19 Gbytes.

b)  ceil(2^32 / 536) = 8,012,999

The segment number is 66 bytes of header joined to every segment to get a cumulative sum of 528,857,934 bytes of header. Therefore, overall number of bytes sent will be 2^32 + 528,857,934 =  4.824 × 10^9 bytes.  Thus, we can conclude that the total time taken to send the file will be 249 seconds over a 155~Mbps link.

8 0
3 years ago
What is the full form of w3c
Xelga [282]
The World Wide Web Consortium, which <span>is an international community where organizations, employees</span><span> and the general public work together to develop Web standards.</span>
7 0
3 years ago
Secure shell (SSH) operates over which port by default
Karolina [17]

Explanation:

By default, SSH opens port 22.

However, this can be arbitrarily changed.  So if port 22 does not work, it is necessary to check the exact/new port number.

5 0
3 years ago
Given numrows and numcols, print a list of all seats in a theater. rows are numbered, columns lettered, as in 1a or 3e. print a
trapecia [35]

/* package whatever; // don't place package name! */

import java.util.*;

import java.lang.*;

import java.io.*;

class NestedLoops {

public static void main (String [] args) {

int numRows = 4;

int numCols = 5;

int i,j;

char ch = 'A';

// Note: You'll need to declare more variables

/* Your solution goes here */

for ( i = 0; i < numRows; i++) { // Outer loop runs for numRows times

for ( j = 0; j < numCols; j++) { // Inner loop runs for numCols times

System.out.print(i+1);

System.out.print((char)(ch+j));

System.out.print(" ");

}

}

System.out.println("");

return;

}

}

8 0
3 years ago
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