Answer:
The answer is "second, third, and fourth choices"
Explanation:
In the question the numbering of the choices were missing if we numbering the choices so, the first choice will be one first number and second choice is in second and so on, and its explanation can be defined as follows:
The network safety key is a type of network login credentials or passwords which is used for provides authorization as well as access the network or device upon which client requests to communicate throughout the form of physical, digital, or biometrical information login.
- It doesn't ensure the extra key.
- It helps ensure there were no additional duplicates.
- It keeps strict access codes as well as keys command.
- It makes sure, that its key could not be linked to able to operate the lock.
Answer:
Currently, raster (bitmap files) and vector graphics are used in web design. But if you want to make a great logo and fully enjoy the use of it you should pick vector graphics for it in the first place. And this is why most designers opt for it.
Explanation:
- Easier to re-edit
- No image distortion
- It is perfect for detailed images
- Vector drawings are scalable
- Vector graphics look better in print
Answer:
Option B (Static NAT) would be the correct choice.
Explanation:
- Static NAT seems to be a method of NAT methodology used to navigate as well as monitor internet usage from some kind of specific public IP address to something like a private IP address.
- Everything always allows the provision of web access to technology, repositories including network equipment inside a protected LAN with an unauthorized IP address.
Some other decisions made aren't relevant to the situation in question. So the above alternative is indeed the right one.
I think it’s B.. I’m pretty sure
Answer:
Latency of an object O is shown below.
Explanation:
W segment and stalled state transmits nothing and waits for acknowledgement. The latency is 2 R TT + the time required for server that are using to transmit the object + the amount of time when server is in stalled state. Let K be the number of window that is K= O/WS .The serveries stalled state where K-1 is period of ime with period lasting RTT-(W-1)S/R
latency = 2RTT +O/R +(K-1)[S/R +RTT - WS/R]
After combining the two case
latency = 2 RTT + O/R + (K-1)[S/R +RTT - WS/R]
where [x] means maximum of (x.0). This is the complete ananlysis of the static windows.
server time for transmit the object is (K-1)[S/R +RTT - WS/R]
