For an event e, p(e)+p(not e) =x, then the value of x^3-3 is a)-2 b)2 c)1 d)-1
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The zero of polynomials is -2. The polynomials is p(y) = .
According to the question,
The polynomials is p(y) = . In order to find the zero of polynomials only if we substitute the value and polynomials become zero.
p(-2) =
= 3(8) + 32 -8
= 0
Hence, the zero of polynomials is -2. The polynomials is p(y) = .
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