All categories

2 years ago

Please help, please and ty.

Mathematics

2 answers:

Dimas [21]2 years ago

8 0

Answer:

l.y=4

m.y=-2x+4

n.1x-1

p.x=-4

Step-by-step explanation:

enot [183]2 years ago

5 0

kgkesgksekgkesgkskg ok

You might be interested in

at a charity basketball game, 450 tickets were sold to students at a school. The remaining x tickets were sold to the public. Th

VladimirAG [237]

Answer:

The number of tickets sold to the public was 375

Step-by-step explanation:

The complete question is

At a charity basketball game, 450 tickets were sold to students at a school. The remaining x tickets were sold to the public. The students paid $15 and public $25. When all the tickets were sold, $10,500 was collected. How many tickets were sold to the public?

Let

x ----> number of tickets sold to the students

y ----> number of tickets sold to the public

we know that

$x+y=450$ ----> equation A

$15x+25y=10,500$ ----> equation B

Solve the system by graphing

The solution is the intersection point both graphs

using a graphing tool

The solution is the point (75,375)

see the attached figure

therefore

The number of tickets sold to the public was 375

6 0

4 years ago

How do you set up the equations?

ch4aika [34]

We will use d for drama and y for yearbook.

d + y = 64
d = y + 10

Now that we have the system if equations we can use substitution where you plug y+10 in for d in the first equation.

(y + 10) + y = 64

2y + 10 = 64

2y = 54

y = 27

If 27 of the 64 are in the yearbook club, 37 are in drama.

3 0

3 years ago

29, 19, 9, -1, ... please help me out;(

anyanavicka [17]

The next one is -11.

7 0

3 years ago

Read 2 more answers

Jenna sells apples and pears. If 20 apples and 60 pears re sold every hour, there will be 80 pears when all the apples are sold.

lutik1710 [3]

Answer:

There are 1,360 pears.

Step-by-step explanation:

Suppose that there are P pears and A apples.

We know that:

"If 20 apples and 60 pears are sold every hour, there will be 80 pears when all the apples are sold."

Suppose that all of these are sold after N hours, then:

20*N = A

80*N = P - 80

We also know that:

"if 60 apples and 20 pears are sold every hour, there will be 400 pears when all the apples are sold."

60*N = A

20*N = P - 400

Then we have four equations:

20*N = A

80*N = P - 80

60*N = A

20*N = P - 400

From the first one and the second one, we get:

20*N = A = 20*N = P - 400

A = P - 400

Now we have 3 equations:

80*N = P - 80

60*N = A

A = P - 400

Now we can just replace the third equation into the second one, then we get:

60*N = A = P - 400

Now we have two equations:

80*N = P - 80

60*N = P - 400

Now, remember that we want to find the number of pears, so we want to find the value of P.

To do it, we can take the quotient of the two equations, so we get:

(80*N)/(60*N) = (P - 80)/(P - 400)

8/6 = (P - 80)/(P - 400)

Now we can solve this for P

(8/6)*(P - 400) = P - 80

(8/6)*P - (8/6)*400 = P - 80

(8/6)*P - P = (8/6)*400 - 80

(2/6)*P = (8/6)*400 - 80

P = (6/2)*( (8/6)*400 - 80 )

P = 3*( (8/6)*400 - 80 ) = 1,360

There are 1,360 pears.

3 0

3 years ago

2x-1/6 = 2(x-3)/3 + 1?

IceJOKER [234]

$2x-\frac{1}{6}=\frac{2(x-3)}{3}+1\ \ \ \ |multiply\ both\ sides\ by\ 6\\\\6(2x)-6(\frac{1}{6})=6\left(\frac{2x-6}{3}\right)+6(1)\\\\12x-1=2(2x-6)+6\\\\12x-1=2(2x)+2(-6)+6\\\\12x-1=4x-12+6\\\\12x-1=4x-6\ \ \ \ |add\ 1\ to\ both\ sides\\\\12x=4x-5\ \ \ \ \ |subtract\ 4x\ from\ both\ sides\\\\8x=-5\ \ \ \ |divide\ both\ sides\ by\ 8\\\\\boxed{\boxed{x=-\frac{5}{8}}}$

7 0

4 years ago

Read 2 more answers