The rectangle has a perimeter P of 58 inches.The length l is one more than 3 times the width w.write and solve a system of linear equations to find the length and width of the rectangle?
Answer:
Length(L)=22 inches
Width(W) = 7 inches
Step-by-step explanation:
GIven:-
Perimeter (p)=58 inches,
Length(L)= one more than 3 times the width(W)
Let, W=x ---------------------------------(equation 1
-----------------------(equation 2)
Here x is unknown and to find the Width(W) we have to find the value of x.
Now,
Perimeter of rectangle(p) = 2 times length(L) + 2 times width(W)

----------------(from equation 1)
----------------(given p=58 inches)




----------------------(equation 3)
Now substituting the value of equation 3 in equation 2.





as,
-----------------------(from equation 1)
inches -------------------(equation 3)
Therefore, Length(L) = 22 inches and Width(W) = 7 inches.
Answer:
x= -2/9
Step-by-step explanation:
2(x-2)/5=4x
2(x-2)=4x*5
2(x-2)=20x
x-2=20x/2
x-2=10x
-2=10x-x
9x= -2
x= -2/9
Answer:
94,080 cm^3
Step-by-step explanation:
V= L • W • H
V= 42 • 35 • 64
V= 94,080
Hope this helps, good luck!
Answer:
Step-by-step explanation:
Batman
we are supposed to find
Which of these properties is enough to prove that a given parallelogram is also a Rectangle?
As we know from the theorem, if the diagonals of a parallelogram are congruent then the parallelogram is a rectangle.
The other options The diagonals bisect each other is not sufficient because in parallelogram diagonals always gets bisected , parallelogram becomes rectangles only if both the diagonals are of same length.
In a parallelogram The opposite angles and opposite sides are always equal.
Hence the correct option is
The diagonals are congruent.