Answer:
And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:
And we can solve for and solving we got:
And from the previous result we got:
And solving we got:
And then we can find the mean with this formula:
So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0
Step-by-step explanation:
For this case we know that the currently mean is 2.8 and is given by:
Where represent the number of credits and the grade for each subject. From this case we can find the following sum:
And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:
And we can solve for and solving we got:
And from the previous result we got:
And solving we got:
And then we can find the mean with this formula:
So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0
that would be 3 minutes and 45 seconds (:
Answer:
1.A 2.yes
Step-by-step explanation:
PEMDAS
Answer:
No, it is not a linear equation
Step-by-step explanation:
This equation contains the term x², meaning that it is a quadratic function (parabola)
So, it is not a linear equation.
If it were a linear equation, x would not be squared, and the equation would have been in y = mx + b form.
The answer is no, it is not a linear equation.
Step-by-step explanation:
By binomial theorem,
T(r+1) = nCr * a^(r+1) * b^r
Term 4 = 7C3 * (2x)^4 * (-5y)^3 = 35 * (16x^4) * (-125y^3) = -70000x^4y^3.