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adelina 88 [10]
3 years ago
10

The initial population of a town is 4100​, and it grows with a doubling time of 10 years. What will the population be in 8 ​year

s?
Mathematics
1 answer:
Marianna [84]3 years ago
3 0
If the population is doubling every 10 years, the rate of change is 100%, for the period of 10 years, so, whatever it happens to be at the time, it grows by 100%, namely it doubles.

\bf \textit{Periodic Exponential Growth}\\\\
A=I(1 + r)^{\frac{t}{p}}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\to &4100\\
r=rate\to 100\%\to \frac{100}{100}\to &1.00\\
t=\textit{elapsed time}\to &8\\
p=period\to &10
\end{cases}
\\\\\\
A=4100(1 + 1)^{\frac{8}{10}}\implies A=4100(2)^{\frac{4}{5}}\implies A=4100\sqrt[5]{2^4}
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