Answer:
The neuron will not fire an action potential.
Explanation:
The missing magnitudes of the synaptic potentials when they reach the postsynaptic cell's axon hillock are:
A. excitatory +7
B. excitatory +10
C. inhibitory -3
D. excitatory +2
E. inhibitory -4
To fire the action potential, the summation of excitatory postsynaptic potentials (EPSP) and inhibitory postsynaptic potentials (IPSP) must reach the action potential threshold, which in this case is 15mV more positive than the resting potential.
The EPSP are: +7 +10 +2= +19
The IPSP are: -3 - 4= -7
EPSP + IPSP=
+19 -7 = +12 mV
The neuron will not fire an action potential since the integration of EPSP and IPSP is below 15mv.
I think the answer is transfer RNA
Errors that may happen in the execution of a factual examination outline. Kinds of trial error incorporate human error or missteps in information section; methodical error, or oversights in the outline of the investigation itself; or irregular mistake, caused by natural conditions or other capricious variables.
