Direct variation is written in the form y = k * x or x = y * k. And, inverse variation is written in the form y = k/x or x = y/k.
For the first problem, if we isolated the y, we would get:
4y = 3x - 1
y = (3/4)x - 1/4
This is written as y = mx + b, which isn’t the form of direct or inverse variation, so the answer is NEITHER.
For the second equation, we could divide by 2 on both sides to isolate x and see if it is in the correct form:
x = 4/y
This is inverse form, so the second question is INVERSE with a constant of variation as 4.
<u>Answer:</u>
The value of x is in the solution set of 3(x – 4) ≥ 5x + 2 is -10
<u>Solution:</u>
Need to determine which value of x from given option is solution set of 3(x – 4) ≥ 5x + 2
Lets first solve 3(x – 4) ≥ 5x + 2
3(x – 4) ≥ 5x + 2
=> 3x – 12 ≥ 5x + 2
=> 3x – 5x ≥ 12 + 2
=> -2x ≥ 14
=> -x ≥ 7
=> x ≤ -7
All the values of x which are less than or equal to -7 is solution set of 3(x – 4) ≥ 5x + 2. From given option there is only one value that is -10 which is less than -7
Hence from given option -10 is solution set of 3(x – 4) ≥ 5x + 2.
2^-2 would become 1/2^2 which becomes 1/4.
Answer:
nomads
Step-by-step explanation:
hope this helps with the work but you do know that this is not history
