The solution to this problem is 5/2a^2b^5
We see from the attached, that kite area = product of the diagonals / 2
The diagonals could be 12 by 8 or
6 by 16 or
3 by 32, etc
It cannot be narrowed down any further.
Answer:
<h2><u><em>
3.5 Km</em></u></h2>
Step-by-step explanation:
the length of the hypotenuse is 4 Km, it is probable that you are looking for the value of the cathetus a.
it is a right triangle and we use Pythagoras
a² = 4² - 2²
a² = 16 - 4
a² = 12
a = √12
a = 3.46 (round 3.5)
Answer:
1779.33 mm³
Step-by-step explanation:
We are given a candle in a form of a cylinder and a cone
Dimensions;
Common radius is 5 mm
Height of the cylinder is 20 mm
Height of the cone is 8 mm
We are required to determine the amount that it can hold.
To answer the question we are going to determine its volume
Cylinder;
Volume of a cylinder is given by;
V = πr²H
Taking π to be 3.14
Then ;
Volume of cylinder = 3.14 × 5mm² × 20 mm
= 1570 mm³
Cone
Volume of a cone is given by;
V = 1/3πr²H
That is;
Volume =1/3 × 3.14 × 5mm² × 8 mm
= 209.33 mm³
Therefore;
Volume of the solid = 1570 mm³ + 209.33 mm³
= 1779.33 mm³
Thus, the volume of the solid is 1779.33 mm³
Hi again............. I am glad to help you again.
6x + 35 + 9x = 15x(x+4) -25
6x + 35 + 9x = 15x² + 60x - 25
15x + 35 = 15x² + 60x - 25
Now, we gonna put all the common terms together
15x - 60x + 35 + 25 - 15x² =
-45x + 60 - 15x² = 0
Now, we need to factorize
-15(x-1)(x+4)=0
Set factors equal to 0
x -1 = 0 or x + 4 = 0
x = 1 or x = 4
I hope that's help !
