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3 years ago

What is E = MC squared

Mathematics

1 answer:

jonny [76]3 years ago

6 0

E represents the units of energy m represents mass and c 2 is the speed of light squared, or multiplied by itself

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A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot

Olegator [25]

Answer:

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, $c_{m}$ = The drag coefficient of the prototype, $c_{p}$

The medium of the test for the model, $\rho_m$ = The medium of the test for the prototype, $\rho_p$

The drag force is given as follows;

$F_D = C_D \times A \times \dfrac{\rho \cdot V^2}{2}$

We have;

$L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m$

Therefore;

$\dfrac{L_p}{L_m} = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2$

$\dfrac{L_p}{L_m} =\dfrac{17}{1}$

$\therefore \dfrac{L_p}{L_m} = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{c_p \times A_p \times \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}$

$\dfrac{A_m}{A_p} = \left( \dfrac{1}{17} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}= \left (\dfrac{17}{1} \right)^2 \times \left( \left\dfrac{17}{1} \right) = 17^3$

$\dfrac{F_m}{F_p} = \left( \left\dfrac{1}{17} \right)^3$ = (1/17)^3 ≈ 0.0002

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ ≈ 0.0002.

5 0

2 years ago

Please help me with this

kondaur [170]

For number 1a. the answer is 7 to 26 or
7:26 or
$\frac{7}{26}$
For number 2a. the answer is 8 to 28 or
8:28 or
$\frac{8}{28} or \frac{2}{7}$
For number 3a. the answer is 12 to 13 or
12:13 or
$\frac{12}{13}$
For number 4a. the answer is 19 to 12 or
19:12 or
$\frac{19}{12}$
For number 5a. the answer is 29 to 10 or
29:10 or
$\frac{29}{10}$
For number 6a. the answer is 11 to 28 or
11:28 or
$\frac{11}{28}$

I just did your homework

4 0

3 years ago

F(x) = x^2 + 8x + 15; Find f(-14/5)

mamaluj [8]

Answer:

either 449/25 or 11/25 depends on the -14/5 or

Step-by-step explanation:

$- \frac{14}{25} or \: \frac{ - 14}{25}$

if it the first one then the answer should be 449/25 but if ut the second one it should be 11/25 .

u just substitute the -14/5 to x then solve

7 0

1 year ago

WILL GIVE BRAINLIEST TO ANSWER

Anika [276]

its x4 got it thanks give me brainliest

7 0

3 years ago

Simplify. (-6x^2 + 2y - 1) + (2x^2-5y + 3) A) -4x^2 + 3y -2 B) -4x^2 - 3y - 2 C) -4x^2 + 3y +2 D) -4x^2 -3y +2

Rasek [7]

Combine like terms

-6x^2+2y + -1 +2x^2 + -5y +3

( -6x^2+2x^2)+(2y-5y)+(-1+3)

= -4x^2+3y+2

Answer : C

I hope that's help !

4 0

3 years ago