we have
----> inequality 1
The solution of the inequality 1 is the shaded area below the solid red line
The solution is the region D and region C
-----> inequality 2
The solution of the inequality 2 is the shaded area above the solid blue line
The solution is the region B and region C
The solution of the system is the common area
so
The solution is the region C
see the attached figure
therefore
the answer is the option C
Region C
So this is going to be an exponential equation, which the format is

, in which a is the initial value and b is the growth/decay rate.
In this case, a is going to be 340,000 and b is going to be 107%, or 1.07, since the population is going to be increasing by 7% and the equation is now

.
Now replace x with 12 and solve.

Solve

, and then if you don't round that answer and multiply it with 340000 you get

.
Answer:
40/.40 = 100
You can buy 100 pounds of food.
Step-by-step explanation:
The equation that represents the <em>sinusoidal</em> function is
,
.
<h3>Procedure - Determination of an appropriate function based on given information</h3>
In this question we must find an appropriate model for a <em>periodic</em> function based on the information from statement. <em>Sinusoidal</em> functions are the most typical functions which intersects a midline (
) and has both a maximum (
) and a minimum (
).
Sinusoidal functions have in most cases the following form:
(1)
Where:
- Angular frequency
- Angular phase, in radians.
If we know that
,
,
,
and
, then the sinusoidal function is:
(2)
(3)
The resulting system is:
(2b)
(3b)
By applying <em>inverse trigonometric </em>functions we have that:
,
(2c)
,
(3c)
And we proceed to solve this system:


,

By (2c):



The equation that represents the <em>sinusoidal</em> function is
,
. 
To learn more on functions, we kindly invite to check this verified question: brainly.com/question/5245372
Answer:
last option
Step-by-step explanation:
It will take 200 / 5 = 40 months for Sara's phone to lose all its value, therefore, the domain is 0 ≤ t ≤ 40 because you can't have negative months. Since negative money is not a thing, the range has to be 0 ≤ V(t) ≤ 200 because it stops at 0 and starts at 200.