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3 years ago

Can someone help me please heeellllppppp.

Mathematics

1 answer:

sveta [45]3 years ago

7 0

Answer:

your answer to (i) is 5 because anything with a denominator of 0 is undefined

Step-by-step explanation:

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3 ft Find the outer perimeter of this figure. Round your answer to the nearest hundredth. Use 3.14 to approximate it. 4 ft 5 ft

Sedbober [7]

Answer:

perimeter = 19.42 ft

Step-by-step explanation:

perimeter of semi circle = 6π/2 = 9.42

perimeter of cone = 5 + 5 = 10

10 + 9.42 = 19.42 ft

7 0

3 years ago

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Which equivalent fraction for 2/3 is? Can someone plz help me

melomori [17]

Answer:

the answer is 4/6 or 6/9

3 0

4 years ago

Can someone help me plssss

lilavasa [31]

Answer:

To get the answer you need to understand the differences between the two in order to use common sense to get the answer

First you’ve got to calculate the inequality which is based on the weather

then look at the multiple choice questions and see which one represents the problem the best and that is… C.

8 0

2 years ago

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Please help quickly im on a test<br> if f(x)=x+4, and g(x)=2x+4, what is f(2)+g(2)?

JulsSmile [24]

Answer:

Step-by-step explanation:

f(2)+g(2)

(2+4)+(2×2+4)

6+8

5 0

3 years ago

An oil refinery is located on the north bank of a straight river that is 2 km wide. A pipeline is to be constructed from the ref

hichkok12 [17]

Answer:

P is exactly 3km east from the oil refinery.

Step-by-step explanation:

Let's d be the distance in km from the oil refinery to point P. So the horizontal distance from P to the storage is 3 - d and the vertical distance is 2. Hence the diagonal distance is:

$\sqrt{(3 - d)^2 + 2^2} = \sqrt{(3 - d)^2 + 4}$

So the cost of laying pipe under water with this distance is

$800000\sqrt{(3 - d)^2 + 4}$

And the cost of laying pipe over land from the refinery to point P is 400000d. Hence the total cost:

$800000\sqrt{(3 - d)^2 + 4} + 400000d$

We can find the minimum value of this by taking the 1st derivative and set it to 0

$800000\frac{2*0.5*(3-d)(-1)}{\sqrt{(3 - d)^2 + 4}} + 400000 = 0$

We can move the first term over to the right hand side and divide both sides by 400000

$1 = 2\frac{3 - d}{\sqrt{(3 - d)^2 + 4}}$

$\sqrt{(3 - d)^2 + 4} = 6 - 2d$

From here we can square up both sides

$(3 - d)^2 + 4 = (6 - 2d)^2$

$9 - 6d + d^2 + 4 = 36 - 24d + 4d^2$

$3d^2-18d+27 = 0$

$d^2 - 6d + 9 = 0$

$(d - 3)^2 = 0$

$d -3 = 0$

d = 3

So the cost of pipeline is minimum when P is exactly 3km east from the oil refinery.

3 0

3 years ago