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Vlad1618 [11]
2 years ago
15

Franklin's faucet was leaking, so he put a bucket underneath to catch the water. After a while, Franklin started keeping track o

f how much water was in the bucket. His data is in the table below.
Mathematics
1 answer:
emmasim [6.3K]2 years ago
6 0
Assuming this is the same problem I answered,

1. Is the relationship linear or nonlinear?
A: The answer is linear since because the number of hours shown increased by 1, the number of quarts increased by 1.5

2. Write the equation for the relationship
A: (x marks the number of hours while y marks the quarts)
m = y2 – y1 / x2 – x1 = 6.5 – 5 / 3 – 2 = 1.5
y – y1 = m(x – x1)
y – 5 = 1.5(x – 2)
y – 5 = 1.5x – 3
y = 1. 5 + 2

3. Using the equation from num. 2, we substitute x = 14.
y = 1.5(14)+2
y = 21+2
y = 23 quarts
You might be interested in
The endpoints of the directed line segment AB are A(−7, 4) and B(8, 9). Find the coordinates of point P along line segment AB so
bekas [8.4K]

Answer:

(-1,5)

Step-by-step explanation:

When a line segment is divided in the ratio m:n, we use the section formula to determine the point P which divides the line segment:

The coordinates of x and y are:

(x,y)=\left(\dfrac{mx_2+nx_1}{m+n}, \dfrac{my_2+ny_1}{m+n}\right)

Given:

A(x_1,y_1)=(-7, 4)\\B(x_2,y_2)=(8, 9)\\AP:PB=m:n=2:3

The coordinates of P is:

(x,y)=\left(\dfrac{2*8+3*-7}{2+3}, \dfrac{2*9+3*4}{2+3}\right)\\=\left(\dfrac{-5}{5}, \dfrac{25}{5}\right)\\\\=(-1,5)

7 0
3 years ago
Describe the slope of the line of best fit
Aliun [14]

Answer:

The graph represent a scatter plot between variable A on the horizpntal line and the variable B on the vertical line.

A line of best fit is a straight line drawn through the maximum number of points on a scatter plot balancing about an equal number of points above and below the line.

As shown by graphinf a line through the maximum number of points, balancing about an equal number of points above and below the line, we can deduce that:

<u>The line of best fit drops from left to right, so the variables have a negative correlation. </u>

3 0
3 years ago
Find the expansion of tan x about the point X = 0.
yan [13]

Answer:

f(x) = x +\frac{1}{3}x^{3}+....

Step-by-step explanation:

As per the question,

let us consider f(x) = tan(x).

We know that <u>The Maclaurin series is given by:</u>

f(x) = f(0) + \frac{f^{'}(0)}{1!}\cdot x+ \frac{f^{''}(0)}{2!}\cdot x^{2}+\frac{f^{'''}(0)}{3!}\cdot x^{3}+......

So, differentiate the given function 3 times in order to find f'(x), f''(x) and f'''(x).

Therefore,

f'(x) = sec²x

f''(x) = 2 × sec(x) × sec(x)tan(x)

      = 2 × sec²(x) × tan(x)

f'''(x) = 2 × 2 sec²(x) tan(x) tan(x) + 2 sec²(x) × sec²(x)

       = 4sec²(x) tan²(x) + 2sec⁴(x)

       = 6 sec⁴x - 4 sec² x

We then substitute x with 0, and find the values

f(0) = tan 0 = 0

f'(0) =  sec²0 = 1

f''(0) = 2 × sec²(0) × tan(0) = 0

f'''(0) = 6 sec⁴0- 4 sec² 0 = 2

By putting all the values in the Maclaurin series, we get

f(x) = f(0) + \frac{f^{'}(0)}{1!}\cdot x+ \frac{f^{''}(0)}{2!}\cdot x^{2}+\frac{f^{'''}(0)}{3!}\cdot x^{3}+......

f(x) = 0 + \frac{1}{1}\cdot x+ \frac{0}{2}\cdot x^{2}+\frac{2}{6}\cdot x^{3}+......

f(x) = x +\frac{1}{3}x^{3}+....

Therefore, the expansion of tan x at x = 0 is

f(x) = x +\frac{1}{3}x^{3}+.....

8 0
4 years ago
Which of the following expressions is equivalent to –6?
Inessa [10]

Answer:

the correct answer po is letter A

Step-by-step explanation:

Tinatamad akong mag explain pero tama po 'yan

8 0
3 years ago
If b√2 = 6, what does b equal? I don't know why I'm stuck on this problem, but could somebody help me?
kotegsom [21]

Answer:

Step-by-step explanation:

Divide both sides by the square root of 2. If you are looking for an exact answer that is rationalized, it would be found by multiplying 6/sqrt(2) * sqrt(2)/sqrt(2) to get

b=\frac{6\sqrt{2} }{2}=3\sqrt{2}

8 0
3 years ago
Read 2 more answers
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