1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
PtichkaEL [24]
3 years ago
15

company is developing a new​ high-performance wax for cross country ski racing. In order to justify the price marketing​ wants,

the wax needs to be very fast.​ Specifically, the mean time to finish their standard test course should be less than 55 seconds for a former Olympic champion. To test​ it, the champion will ski the course 8 times. The​ champion's times are 59.5​, 64.7​, 46.6​, 54.8​, 47.1​, 46.1​, 52.2​, and 41.6 seconds to complete the test course. Complete parts a and b below. ​a) Should they market the​ wax? Assume the assumptions and conditions for appropriate hypothesis testing are met for the sample. Assume alphaequals0.05. What are the null and alternative​ hypotheses? Choose the correct answer below. A. H0​: muless than55 vs. HA​: muequals55 B. H0​: muequals55 vs. HA​: mugreater than55 C. H0​: mugreater than55 vs. HA​: muequals55 D. H0​: muequals55 vs. HA​: muless than55'
Mathematics
1 answer:
lukranit [14]3 years ago
4 0

Answer:

Correct option: (D) <em>H₀</em>: <em>μ</em> =  55 vs. <em>Hₐ</em>: <em>μ</em> < 55.

Step-by-step explanation:

In this case we need to test whether the new​ high-performance wax price is justifiable or not.

It is provided that the wax needs to be very fast specifically the mean time to finish their standard test course should be less than 55 seconds for a former Olympic champion, for the price to justifiable.

So, to test this a sample of <em>n</em> = 8 champion's times are recorded.

A one-sample <em>t</em>-test will be used to perform the test.

The hypothesis to test this is defined as follows:

<em>H₀</em>: The mean time to finish their standard test course is 55 seconds, i.e. <em>μ</em> =  55.

<em>Hₐ</em>: The mean time to finish their standard test course is less than 55 seconds, i.e. <em>μ</em> < 55.

Thus, the correct option is (D).

You might be interested in
(x + 1)(x + 2)(x + 1)(3x + 2)
Lapatulllka [165]

Answer:

Is it the full question I mean what does it want next anyway?

But here's your answer :

3x^4 + 14x^3 + 23x^2 + 16x + 4

6 0
2 years ago
What was the average grade earned?
Anettt [7]
A 3 I guess or a B. idk....
5 0
3 years ago
4x-3=5x-21 what does x=
torisob [31]
U subtract 4x by 5x and then you add 3 by -21 and the answer is x=18
3 0
4 years ago
If you take a number multiply by 7 then takeaway 1. You get the same as if you took the number multiply by 5 then takeaway 8. Wh
muminat
7x - 1 = 5x - 8
Minus 5x on each side
2x -1 = -8
Plus 1 on each side
2x = -7
Divide by 2 on each side
x = -7/2

The number is most likely -7/2
7 0
3 years ago
Read 2 more answers
Math Help Please....
stich3 [128]
Triangle ABE is similar to triangle CED (AAA)
10/8 = (2x+6) / (x+6)
x=2
therefore AE = 2(2) + 6
= 10 units
5 0
3 years ago
Other questions:
  • What is 60400239 in word form
    10·2 answers
  • Gary ate 21/25 of his candy bar. What percent of the candy bar did Gary eat?
    6·2 answers
  • Pls help me I’m struggling
    8·2 answers
  • How do you unblock things on a cromebook?
    14·2 answers
  • How old will I be in 2020 if my birthday is september 14, 1995?
    13·2 answers
  • PLEASE HELP Harold purchased a new snowmobile. The dealer gave him an option to pay the purchase price of dollars at 100 dollars
    14·2 answers
  • Together, Iris and Ivan weigh 120 pounds. Iris weighs 10 pounds less than Ivan. How much does each child weigh?​
    7·2 answers
  • Find the slope and y intercept
    6·1 answer
  • Q: Out of 20 attempts a basketball player scored 8 times. What percent of
    14·2 answers
  • Find the surface area of this rectangular prism. Be sure to include the correct unit in your answer.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!