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PtichkaEL [24]
3 years ago
15

company is developing a new​ high-performance wax for cross country ski racing. In order to justify the price marketing​ wants,

the wax needs to be very fast.​ Specifically, the mean time to finish their standard test course should be less than 55 seconds for a former Olympic champion. To test​ it, the champion will ski the course 8 times. The​ champion's times are 59.5​, 64.7​, 46.6​, 54.8​, 47.1​, 46.1​, 52.2​, and 41.6 seconds to complete the test course. Complete parts a and b below. ​a) Should they market the​ wax? Assume the assumptions and conditions for appropriate hypothesis testing are met for the sample. Assume alphaequals0.05. What are the null and alternative​ hypotheses? Choose the correct answer below. A. H0​: muless than55 vs. HA​: muequals55 B. H0​: muequals55 vs. HA​: mugreater than55 C. H0​: mugreater than55 vs. HA​: muequals55 D. H0​: muequals55 vs. HA​: muless than55'
Mathematics
1 answer:
lukranit [14]3 years ago
4 0

Answer:

Correct option: (D) <em>H₀</em>: <em>μ</em> =  55 vs. <em>Hₐ</em>: <em>μ</em> < 55.

Step-by-step explanation:

In this case we need to test whether the new​ high-performance wax price is justifiable or not.

It is provided that the wax needs to be very fast specifically the mean time to finish their standard test course should be less than 55 seconds for a former Olympic champion, for the price to justifiable.

So, to test this a sample of <em>n</em> = 8 champion's times are recorded.

A one-sample <em>t</em>-test will be used to perform the test.

The hypothesis to test this is defined as follows:

<em>H₀</em>: The mean time to finish their standard test course is 55 seconds, i.e. <em>μ</em> =  55.

<em>Hₐ</em>: The mean time to finish their standard test course is less than 55 seconds, i.e. <em>μ</em> < 55.

Thus, the correct option is (D).

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A devastating freeze in California's Central Valley in January 2007 wiped out approximately 75% of the state's citrus crop. It t
solniwko [45]

The relationship between the percentage of frozen citrus crop, and the cost of box of oranges is an illustration of a linear function.

  • <em>The linear equation of the function is: </em>g(P) = 22.9P+7<em>.</em>
  • <em>The inverse function is: </em>g^{-1}(c) = \frac{1}{22.9}(c - 7)<em> .</em>
  • <em>A practical domain is from 0% to 100%</em>
  • <em>A practical range is from 7 to 29.9 </em>

<u>A. Input quantity</u>

The input quantity is the percentage of frozen citrus crop

<u />

<u>B. Output quantity </u>

The output quantity is the cost of box of oranges

<u>C. The linear function</u>

We have:

(P_1,c_1) = (20\%,11.58)\\(P_2,c_2) = (80\%,25.32)

<em>Calculate the slope of the function</em>

m = \frac{c_2 - c_1}{P_2 - P_1}

m = \frac{25.32 - 11.58}{80\%-20\%}

m = \frac{13.74}{60\%}

m = 22.9

<em>The linear equation is calculated as follows:</em>

c -c_1 = m(P-P_1)

c -11.58= 22.9(P-20\%)

c-11.58 = 22.9P-4.58

<u>D. Rewrite as y = mx + b</u>

We have:

c-11.58 = 22.9P-4.58

Collect like terms

c = 22.9P - 4.58 + 11.58

c = 22.9P+7

<em>The function is:</em>

g(P) = 22.9P+7

<u>E. A practical domain</u>

The domain is the possible values of P.  Because P is a percentage, its possible values are 0% to 100%.

The domain of the function is: [0\%,100\%]

<u>F. A practical range</u>

When P = 0%

c = 22.9 \times 0\% + 7 = 7

When P = 100%

c = 22.9 \times 100\% + 7 = 29.9

Hence, the range of the function is: [7,29.9]

G. The meaning of g^{-1}(12)

The inverse function of g(P) is g^{-1}(P)

So:

g^{-1}(12) is the percentage of frozen citrus crop, when the cost is $12.

<u>H. The inverse formula</u>

We have:

c = 22.9P+7

Subtract 7 from both sides

c - 7 = 22.9P

Make P the subject

P = \frac{1}{22.9}(c - 7)

So, the inverse formula is:

g^{-1}(c) = \frac{1}{22.9}(c - 7)

Substitute 12 for c

g^{-1}(12) = \frac{1}{22.9}(12 - 7)

g^{-1}(12) = \frac{1}{22.9} \times 5

g^{-1}(12) = 22\%

Read more about linear equations at:

brainly.com/question/19770987

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An electrician needs 18.25 feet of wire for each outlet she installs. How man can she install with a 50 ft spool of wire?
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Answer:

2

Step-by-step explanation:

Ok, so if we know how much wire is needed for one outlet, we must figure out how many 18.25s fit into 50 ft of wire.

18.25*2=36.5

18.25*3=54.75 which is over 50 so it cannot possibly be more than 2.

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The question is for any rational function. I give one example in picture below. There we can see that first part of the "rule" is true. we indeed have vertical asymptotes at every x value where denominator is zero in this case x = 3 and x = 1. but second part of the rule is not true. we can see that if we inverse x ( we have factor that looks like a - x we get positive function between asymptotes.

Answer is False

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Please help me with part (iii). If possible help me check my answers too. Thanks​
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LINK: https://www.mayoclinic.org/diseases-conditions/urine-color/symptoms-causes/syc-20367333

I HOPE THIS HELPS. IF IT DOES, PLEASE MARK BE AS BRAINLIEST. EVERYTHING ELSE IS CORRECT EXEPT (i)

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