All categories

2 years ago

|x-5|>6 Please help me thank you

Mathematics

1 answer:

tensa zangetsu [6.8K]2 years ago

5 0

Answer:

x<-1 or x>11

Step-by-step explanation:

Set the equation x-5>6 and solve. You would then get x>11

For the second part, you want to flip the > sign into < and turn the 6 into -6. Solve the equation to get x-5<-6 which is then x<-1

You might be interested in

Parallelogram JKLM is shown on the coordinate plane below:

bulgar [2K]

The real answer is b

4 0

4 years ago

5z+7=3 what solution

Maru [420]

Answer:

z = -4/5

Step-by-step explanation:

5z + 7 = 3

5z = -7 + 3

5z = -4

z = -4/5

Hope this helps :)

Let me know if there are any mistakes!!

6 0

3 years ago

Convert the given amount to the given unit: 9 yards; meters

katrin [286]

9 yards is about 8 meters

6 0

3 years ago

X/3=-19<br> What is the value of x

Molodets [167]

<h3>I'll teach you how solve X/3=-19</h3>

-----------------------------------------------

X/3=-19

Multiply both sides by 3:

3x/3= 3(-19)

Simplify:

x= -57

Your Answer Is x= -57

plz mark me as brainliest :)

8 0

3 years ago

Read 2 more answers

If a fire is burning a building and it takes 2 hours to put it out using 2000 gal./min., what minimum diameter cylindrical tank

strojnjashka [21]

Answer:

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

Step-by-step explanation:

A gallon equals 0.134 cubic feet. First, we determine the amount of water ( $Q$ ), measured in cubic feet, needed to put out the fire under the assumption that water is consumed at constant rate:

$Q = \dot Q \cdot \Delta t$ (1)

Where:

$\dot Q$ - Volume rate, measured in feet per minute.

$\Delta t$ - Time, measured in minutes.

If we know that $\dot Q = 2000\,\frac{gal}{min}$ and $\Delta t = 120\,min$ , then the amount of water is:

$Q = \left(2000\,\frac{gal}{min} \right)\cdot (120\,min) \cdot \left(0.134\,\frac{ft^{3}}{gal} \right)$

$Q = 32160\,ft^{3}$

And the diameter of the cylindrical tank based on the capacity found above is determined by volume formula for a cylinder:

$Q = \frac{\pi}{4}\cdot D^{2}\cdot h$ (2)

Where:

$D$ - Diameter, measured in feet.

$h$ - Height, measured in feet.

If we know that $Q = 32160\,ft^{3}$ and $h = 12\,ft$ , then the minimum diameter is:

$D^{2} = \frac{4\cdot Q}{\pi\cdot h}$

$D = 2\cdot \sqrt{\frac{Q}{\pi\cdot h} }$

$D = 2\cdot \sqrt{\frac{32160\,ft^{3}}{\pi\cdot (12\,ft)} }$

$D \approx 58.415\,ft$

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

8 0

3 years ago