Answer:
9/2 if n goes to infinity and that the 2n^3 is under the whole expression
Step-by-step explanation:
Let me clear this .
find limit (9n^3 + 5*n - 2)/ (2n^3)
as n --> infinity
Did I put the parentheses in the right spot?
because if you leave it the way you did, then the whole expression goes to positive infinity as n goes to infinity But I will do this with parentheses
so
find limit (9n^3 + 5*n - 2)/ (2n^3)
simplify expression
limit (9/2) + 5/(2n^2) - 1/(n^3)
= (9/2) + 0 - 0
= (9/2)
Step-by-step explanation:
Answer:
2i and -2i
Step-by-step explanation:
I'll change u to x to be easier to understand.
x^2 = -4
sqrt(x^2) = sqrt(-4)
sqrt(-4) = 2i, or -2i
<span>Look
for the sum of 56 and 64, written as the product of its GCF and another sum.
First, let’s find the greatest common factor of both given numbers:
=> 56 = 1, 2, 4, 7, 8, 13, 28 and 56
=> 64 = 1, 2, 4, 8, 16, 32, and 64
Now, we need to find the greatest common factor between the two numbers. The GCF
of the 2 numbers is 8.
=> 56 / 8 = 7
=> 64 / 8 = 8
=> 56 + 64 = 120
=> (8 x 7) + (8 x 8)
=> 56 + 64
=> 120.</span><span>
</span>
The format is y = mx + b
where y would be your C
x would be your M
m would be the price per mile (2.20)
and b would be your initial fee (2.75)
put this together in that format and we get
C = 2.20M + 2.75
