F(x) = 3x^2+6x-2
= 3(x^2+2x-2/3)
= 3(x^2 +2x + 1 - 1 - 2/3)
= 3((x+1)^2 - 1 - 2/3)
= 3((x+1)^2 -5/3))
= 3(x+1)^2 - 5
So our function is in the form:
f(x) = 3(x+1)^2 - 5
where a = 3, h = -1, k = -5
Answer:
90
Step-by-step explanation:
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Answer:

Step-by-step explanation:
An arithmetic sequence that is described by the explicit formula ...

can also be described by the recursive formula ...

Matching parts of the formulas, we see that a1 = 4, d = -7. Putting these values into the explicit formula gives ...

Answer:
hello thanks for the f.r.e.e points saving
to give 100 Satep-by-step explanation: