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Masteriza [31]
2 years ago
13

What's the answer to this 3 2/7 x 1/5

Mathematics
2 answers:
Eduardwww [97]2 years ago
6 0
The answer would be 23/35 :,) if I’m not wrong.
HACTEHA [7]2 years ago
3 0
It should be 23/35 as the answer
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Fill in the 3 blank boxes
Ket [755]
First one is 1 x 10^6
second is 2 x 10^8
third one is 157 times
6 0
3 years ago
Estimate the sum or difference, Use the benchmarks 0, 1/2, 1.
Oksana_A [137]
It is B might might be wing :/
5 0
3 years ago
Please solve with explanation
castortr0y [4]

Answer:

The amount of wood left is 36 9/16 in

Step-by-step explanation:

Here, we want to get the amount of wood left

To calculate this, we have to subtract what is cut and what is wasted from the original total length

So we have what is left as follows;

45 1/2 - 8 7/8 - 1/16

45 1/2 = 91/2

8 7/8 = 71/8

91/2 - 71/8 - 1/16

(728 - 142 - 1)/16

585/16 = 36 9/16 in

6 0
3 years ago
The hypotenuse of a 45 -45 -90 triangle measures 128 cm what is the length of one leg of the triangle
erma4kov [3.2K]
This is an isosceles triangle. The definition of an isosceles triangle is a triangle with at least two congruent sides and angles. If 2 angles on a triangle are congruent (in this case 45 and 45 are two congruent angles) then triangle is isosceles. Therefore the two sides of triangle will be congruent. We know that the triangle is a right triangle because it has a hypotenuse. If a triangle has a hypotenuse then it's a right triangle. We can apply the Pythagorean theorem: a^2 + b^2 = c^2
A and B are the legs and C is the hypotenuse.
We can plug C in the equation:
a^2 + b^2 = 128
What do we know about the legs of the isosceles triangle? They are congruent so a and b have to be equal. From here it's simply guess and check. Will 8 work?
8^2 + 8^2 = 128
64 + 64 = 128
128=128
Yes the value 8 works so the length of two legs of the triangle is 8.
4 0
3 years ago
Read 2 more answers
Solve 4 square root of 3 = 8cos
sukhopar [10]

Therefore \theta = 30^\circ

Step-by-step explanation:

Given,

4\sqrt{3 } =8 cos \theta

\Leftrightarrow cos \theta =\frac{4\sqrt{3} }{8}

\Leftrightarrow cos \theta =\frac{\sqrt{3} }{2}

\Leftrightarrow cos \theta =cos 30^\circ

\Leftrightarrow  \theta = 30^\circ

Therefore \theta = 30^\circ

4 0
3 years ago
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