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Alika [10]
3 years ago
5

35 POINTS!!! Laura is constructing an inscribed square. Gavin is constructing an inscribed regular hexagon. In your own words, d

escribe one difference between Laura's construction steps and Gavin's construction steps. (10 points)
Mathematics
1 answer:
Nikolay [14]3 years ago
7 0
One is a square with 4 sides and the other is a hexagon with 8
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The table below shows the heights of several books. Jean stacks a dictionary on top of her novel. How high is the stack of the t
aev [14]

<u><em>Answer:</em></u>

The height of the stack = 5\frac{1}{4} in

<u><em>Explanation:</em></u>

We are given that Jean stacks a dictionary on top of a novel.

This means that the total height of the stack will be equal to the height of the dictionary added to the height of the novel.

<u>From the givens, we have:</u>

height of dictionary = 4\frac{1}{2} in

height of novel = \frac{3}{4} in

<u>Now, adding the two height, we will have:</u>

Total height of stack = height of novel + height of dictionary

Total height of stack = \frac{3}{4}+4 \frac{1}{2} = \frac{3}{4}+ \frac{18}{4}= \frac{21}{4}=5 \frac{1}{4} in

Hope this helps :)

6 0
3 years ago
Arrange the numbers in increasing order 5.049, 5.069, 5.49, 5.09
s344n2d4d5 [400]

5.049 is the smallest

5.069

5.09

5.49 is the biggest

3 0
3 years ago
Read 2 more answers
A simple random sample of 90 is drawn from a normally distributed population, and the mean is found to be 138, with a standard d
bagirrra123 [75]

The 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C:  [130.10, 143.90]

<h3>
How to find the confidence interval for population mean from large samples (sample size > 30)?</h3>

Suppose that we have:

  • Sample size n > 30
  • Sample mean = \overline{x}
  • Sample standard deviation = s
  • Population standard deviation = \sigma
  • Level of significance = \alpha

Then the confidence interval is obtained as

  • Case 1: Population standard deviation is known

\overline{x} \pm Z_{\alpha /2}\dfrac{\sigma}{\sqrt{n}}

  • Case 2: Population standard deviation is unknown.

\overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}

For this case, we're given that:

  • Sample size n = 90 > 30
  • Sample mean = \overline{x} = 138
  • Sample standard deviation = s = 34
  • Level of significance = \alpha = 100% - confidence = 100% - 90% = 10% = 0.1 (converted percent to decimal).

At this level of significance, the critical value of Z is: Z_{0.1/2} = ±1.645

Thus, we get:

CI = \overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}\\CI = 138 \pm 1.645\times \dfrac{34}{\sqrt{90}}\\\\CI \approx 138 \pm 5.896\\CI \approx [138 - 5.896, 138 + 5.896]\\CI \approx [132.104, 143.896] \approx [130.10, 143.90]

Thus, the 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C:  [130.10, 143.90]

Learn more about confidence interval for population mean from large samples here:

brainly.com/question/13770164

3 0
2 years ago
There are a total of 115 first graders, 225 second graders, and 140 third graders, who are going on a field trip. If a bus holds
alina1380 [7]
<span>Total number of students: 115 + 225 + 140 = 480 Number of buses needed: 480 ÷ 80 = b
b = 6</span>
5 0
3 years ago
Read 2 more answers
Margo borrows $1900, agreeing to pay it back with 4% annual interest after 9 months. How much interest will she pay?
lana66690 [7]

1900*4%

1900*0.04

76 (interest for a year)

76*3/4 (3/4 because 9 months is 3/4 of a year)

57 (9 months interest)

Margo will pay $57 in interest  



5 0
3 years ago
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