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Mazyrski [523]
3 years ago
5

Each problem has something wrong with it

Mathematics
2 answers:
goldenfox [79]3 years ago
8 0

Answer:

See below

Step-by-step explanation:

In the 1st problem, the negative wasn't distributed to the 4, so the expression should read 2x-3y-4 instead

In the 2nd problem, the 3 wasn't distributed to the -2, so the expression should read 5x+3x-6 instead

In the 3rd problem, it should read 30x² since x*x=x².

In the 4th problem, x is multiplied by both y and z, so the expression should read xyz instead.

In the 5th problem, a should only be multiplied by x in the fraction since a is equivalent to a/1, making the denominator stay the same. So, the expression should read ax/y instead.

In the 6th problem, the exponent distributes to BOTH 4 and x, so the expression should read 16x² instead.

In the 7th problem, the exponent distributes to both the numerator and denominator, so the expression should read x³/y³ instead.

In the 8th problem, you cannot square root each individual term. Therefore, the expression should not be rewritten.

In the 9th problem, you cannot distribute the radical for each term. Therefore, the expression should not be rewritten.

In the 10th problem, the rewritten expression is missing 2ab. So, (a+b)²=a²+2ab+b²

In the 11th problem, there are no parentheses, so -(3²) was done instead of (-3)².

In the 12th problem, when the negative is distributed to the 5, we have -5+5=0 which is not -10. The resulting expression should be written as x²-x+10

zhuklara [117]3 years ago
7 0

Answer:

Step-by-step explanation:

1)It should be   (-4)

2) It should be  (-6) Not (-2)

3) It should be 30x²

4) It should be xyz

5) It should be \frac{ax}{y}

6) 16x²

7) \dfrac{x^{2}}{y^{2}}

8) \sqrt{25-x^{2}}

9)\sqrt{x+9}

10) a² + b² +2ab

11) -9

12)x² - x + 0

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