2 years ago

If the sphere shown has a radius of 9 units, what is the volume of the sphere?

Mathematics

1 answer:

kirill [66]2 years ago

6 0

V = 4/3 * 3.14 * 9^3 = 3052.08

Answer is B

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Jamir buys a Snickers bar that weighs 16.5 ounces. He takes 6 bites. How many ounces are in each bite?

san4es73 [151]

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Step-by-step explanation:

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Find point A ( x, y ) if point B is ( 6 , 10 ) and the midpoint between A and B is ( -4,5)

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(14,0)

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3 years ago

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Tpy6a [65]

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2 years ago

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3 years ago

A curve is given by y=(x-a)√(x-b) for x≥b, where a and b are constants, cuts the x axis at A where x=b+1. Show that the gradient

ankoles [38]

<u>Answer:</u>

A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.

<u>Solution:</u>

We need to show that the gradient of the curve at A is 1

Here given that ,

$y=(x-a) \sqrt{(x-b)}$ --- equation 1

Also, according to question at point A (b+1,0)

So curve at point A will, put the value of x and y

$0=(b+1-a) \sqrt{(b+1-b)}$

0=b+1-c --- equation 2

According to multiple rule of Differentiation,

$y^{\prime}=u^{\prime} y+y^{\prime} u$

so, we get

${u}^{\prime}=1$

$v^{\prime}=\frac{1}{2} \sqrt{(x-b)}$

$y^{\prime}=1 \times \sqrt{(x-b)}+(x-a) \times \frac{1}{2} \sqrt{(x-b)}$

By putting value of point A and putting value of eq 2 we get

$y^{\prime}=\sqrt{(b+1-b)}+(b+1-a) \times \frac{1}{2} \sqrt{(b+1-b)}$

$y^{\prime}=\frac{d y}{d x}=1$

Hence proved that the gradient of the curve at A is 1.

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2 years ago