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Arisa [49]
3 years ago
12

I'm stuck :/ help hurry​

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
4 0

Answer: i think A is negative -2 and B is -19 hope this help im not a hundred percent sure if i got it wrong please let know.

Step-by-step explanation:

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Answer:

x = 3.9

Step-by-step explanation:

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x = 3.9

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Given the parent function f(x) = x give the best description of the graph of y = x3 +3.
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Step-by-step explanation:

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3 years ago
Enter the correct answer in the box. solve the equation x2 − 16x 54 = 0 by completing the square. fill in the values of a and b
poizon [28]

The roots of the given polynomials exist  $x=8+\sqrt{10}$, and $x=8-\sqrt{10}$.

<h3>What is the formula of the quadratic equation?</h3>

For a quadratic equation of the form $a x^{2}+b x+c=0$ the solutions are

$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Therefore by using the formula we have

$x^{2}-16 x+54=0$$

Let, a = 1, b = -16 and c = 54

Substitute the values in the above equation, and we get

$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$

simplifying the equation, we get

$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\

$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\

$&x=8+\sqrt{10}, x=8-\sqrt{10}

Therefore, the roots of the given polynomials are $x=8+\sqrt{10}$, and

$x=8-\sqrt{10}$.

To learn more about quadratic equations refer to:

brainly.com/question/1214333

#SPJ4

3 0
1 year ago
Read 2 more answers
Please hurry it’s missing and I need it fast
sattari [20]
2. 83 R 2
3. 82 R 1111 etc
3 0
2 years ago
Read 2 more answers
1.
DaniilM [7]
Um answer f I don’t know math I’m really bad at it
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2 years ago
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