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Rzqust [24]
2 years ago
12

Y=3x+5 when x=10 what is the value of y

Mathematics
2 answers:
LiRa [457]2 years ago
4 0

Answer:

Y = 35.

Step-by-step explanation:

Okay so we have the equation Y = 3x + 5. Let's make this simpler and make x into 10, now we have Y = (3x10) + 5 = Y = 30 + 5.

All we need to do now is do a reverse equation. 30 + 5 = Y. Well, 30 + 5 = 35 so there's your answer. Y = 35.

Hope that helps. x

Strike441 [17]2 years ago
3 0

Answer:

y = 35

Step-by-step explanation:

y = 3*(10) + 5

y = 30 + 5

y = 35

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9. Miguel measures 5 kg of rice. One kilogram is approximately equal to 2.2 pounds. Which
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Answer: 11

Step-by-step explanation:

One kilogram is equal to 2.2 pounds so all you would have to do is multiply 2.2 x 5 and you get 11. :)

8 0
4 years ago
88.83 is what percent of 21?
ozzi
423%. Calculate this with \frac{88.83}{21}
5 0
4 years ago
Read 2 more answers
PLZ LOOK AT THE IMAGE AND PLZ TELL ME THE ANSWER I WILL GIVE BRAINLESS
raketka [301]

Answer:

a) Unit price :

  • 12 cupcakes for $29 = $2.42
  • 50 cupcakes for $129 = $2.58

Reasoning:

  • 12 cupcakes for $29 = $29 ÷ 12 cupcakes which gives 2.416666667 and if rounded off gives you $2.42.
  • 50 cupcakes for $129 = $2.58 accurately.

b) 12 cupcakes for $29 gives the lowest unit price as $2.42 is less than $2.58.

<em>I hope this answer will help you !!!!</em>

7 0
3 years ago
Find the y intercept of the line on the graph
saul85 [17]
It’s the vertical line on the graph
4 0
2 years ago
Suppose that 40 percent of the drivers stopped at State Police checkpoints in Storrs on Spring Weekend show evidence of driving
lesantik [10]

Answer:

a) 0.778

b) 0.9222

c) 0.6826

d) 0.3174

e) 2 drivers

Step-by-step explanation:

Given:

Sample size, n = 5

P = 40% = 0.4

a) Probability that none of the drivers shows evidence of intoxication.

P(x=0) = ^nC_x P^x (1-P)^n^-^x

P(x=0) = ^5C_0  (0.4)^0 (1-0.4)^5^-^0

P(x=0) = ^5C_0 (0.4)^0 (0.60)^5

P(x=0) = 0.778

b) Probability that at least one of the drivers shows evidence of intoxication would be:

P(X ≥ 1) = 1 - P(X < 1)

= 1 - P(X = 0)

= 1 - ^5C_0 (0.4)^0 * (0.6)^5

= 1 - 0.0778

= 0.9222

c) The probability that at most two of the drivers show evidence of intoxication.

P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)

^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2  (0.4)^2  (0.6)^3

= 0.6826

d) Probability that more than two of the drivers show evidence of intoxication.

P(x>2) = 1 - P(X ≤ 2)

= 1 - [^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2 * (0.4)^2  (0.6)^3]

= 1 - 0.6826

= 0.3174

e) Expected number of intoxicated drivers.

To find this, use:

Sample size multiplied by sample proportion

n * p

= 5 * 0.40

= 2

Expected number of intoxicated drivers would be 2

7 0
3 years ago
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