Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.
<h3>How far did the outfielder throw the ball?</h3>
Based on the shape of a mound, the law of cosines can be used.
The distance the ball was thrown by the outfielder can therefore be d.
Distance is:
d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))
d ²= 33,484.42ft
Then find the square root:
d = √33,484.42
= 182.9874
= 183 ft
Find out more solving for distance at brainly.com/question/10739348
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> hello there stranger
The area of a circle is pi times the radius squared (A = π r²).
Answer:
-27
Step-by-step explanation:
-5-9=-14
-14-13=-27
Answer:
600 volts
Step-by-step explanation:
Given =
A = 12 ampere
V = 480 volts
A2 = 15 ampere
Solution =
R = V/I
= 480 / 12
= 40 ohms
R = V / I
V = R x I
= 40 x 15
= 600 volts
