By addition of all the exercise and substracting it from 1 hourJavier runs on treadmill on Monday is 0.40 hour.
Now According to the question javier completed 3 repetitions of each exercise so by multiplication time taken by javier to complete each exercise is as follow;
Squats = 0.8*3= 0.24 hour
Crunches = 0.03*3 = 0.09 hour
Lunges = 0.04*3 = 0.12 hour
curls = 0.05*3 = 0.15 hour
we can calculate total time taken to complete all exercise by Addition is,
0.24 + 0.09 + 0.12 + 0.15
0.60 hour
time taken on treadmill by javier;
1 hour - 0.60 hour
0.40 hour
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The ordered pairs which lie on the graph of the exponential function, f(x) = 3(0.2)^x is; Choice A; (0, 3).
<h3>Ordered pair Solution;</h3>
The given exponential function is;
By testing all values; Only the pair; (0, 3) is a solution to the graph of the exponential given.
By testing;
- Where, (0.2)⁰ = 1 (from indices).
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Answer:
a) 40.13% probability that a laptop computer can be assembled at this plant in a period of time of less than 19.5 hours.
b) 34.13% probability that a laptop computer can be assembled at this plant in a period of time between 20 hours and 22 hours.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:

a)Less than 19.5 hours?
This is the pvalue of Z when X = 19.5. So



has a pvalue of 0.4013.
40.13% probability that a laptop computer can be assembled at this plant in a period of time of less than 19.5 hours.
b)Between 20 hours and 22 hours?
This is the pvalue of Z when X = 22 subtracted by the pvalue of Z when X = 20. So
X = 22



has a pvalue of 0.8413
X = 20



has a pvalue of 0.5
0.8413 - 0.5 = 0.3413
34.13% probability that a laptop computer can be assembled at this plant in a period of time between 20 hours and 22 hours.