Question

Solve:

Answer 1

The solutions to the equation $3-k=\sqrt{3k+1}$ are k = 1 and 8

The given equation is:

$3-k=\sqrt{3k+1}$

Square both sides of the equation

$(3-k)^2=3k+1$

Expand the left side of the equation above

$(3-k)^2=3k+1\\\\(3-k)(3-k)=3k+1\\\\3^2-3k-3k+k^2=3k+1\\\\9-6k+k^2=3k+1$

Write the quadratic equation in standard form

$k^2-6k-3k+9-1=0\\\\k^2-9k+8=0$

Factor the quadratic equation

$(k-8)(k-1)=0$

Use the zero product property

k - 8 = 0

k = 8

k - 1 = 0

k = 1

The solutions to the equation $3-k=\sqrt{3k+1}$ are k = 1 and 8

Learn more here: brainly.com/question/25840704

Answer 2

answer

first one: 8 and 1

second one: is 1

Step-by-step explanation:

slay