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Delvig [45]
3 years ago
14

if you select one card at random from a standard deck of 52 cards , what is the probability of that card being a 3,4,or 5?

Mathematics
1 answer:
Aleks04 [339]3 years ago
6 0
Since there’s four of each card, there would be 12
12 out of 52 cards would be 3,4, or 5
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Nadusha1986 [10]
Four thousand 3 hundredths
5 0
3 years ago
Divide round to the nearest tenth 0.197 divided by 3.0
katovenus [111]

Answer:

0.657 I think this is the answer or it's 0.065 hehe

4 0
3 years ago
The simplest form of sqrt 80 can be written as a sqrt b where a = and b =
Zanzabum

The square root of 80 can be broken up into the square root of 16 x square root of 5. We know that the square root of 16 is 4. So in the form (a sqrt b)

A would be 4 and b would be 5.

Answer: 4 sqrt 5

5 0
3 years ago
Read 2 more answers
Calculate the average rate of change of f(x) = 1 x - x2 - 2 for 3 ≤ x ≤ 6. A) -163 18 B) -18 163 C) 163 18 D) 18 163
larisa86 [58]
To solve this we are going to use the average rate of change formula: A(x)= \frac{f(b)-f(a)}{b-a}
where
A(x) is the average rate of change of the function
f(a) is the position function evaluated at a
f(b) is the position function evaluated at b
a is the first point in the interval
b is the second point in the interval

We can infer for our problem that the first point is 3 and the second point is 6, so a=3 and b=6. Lets replace those values in our formula:
A(x)= \frac{f(b)-f(a)}{b-a}
A(x)= \frac{f(6)-f(3)}{6-3}
A(x)= \frac{6-6^2-2-(3-3^2-2)}{3}
A(x)= \frac{-32-(-8)}{3}
A(x)= \frac{-32+8}{3}
A(x)= \frac{-24}{3}
A(x)=-8

We can conclude that the average rate of change of the function f(x) = 1 x - x2 - 2 for <span>3 ≤ x ≤ 6 is -8</span>
3 0
3 years ago
Read 2 more answers
HEEEEEELP MEEEEEEEEEEEE
adell [148]
You have to say please
3 0
3 years ago
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