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2 years ago

HELPP I‘LL GIVE BRAINLIEST!

Mathematics

1 answer:

TiliK225 [7]2 years ago

8 0

Answer:

so Omar approximately receives 393€

please mark brainliest!♡♡

Step-by-step explanation:

2000/5.087= 393.15903

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Help look at picture!

Luda [366]

Answer:

Step 1: Set x to 0

$-2(0) + y = 3$

$y = 3$

(0, 3)

Step 2: Set x to 1

$-2(1) + y = 3$

$-2 + y + 2 = 3 + 2$

$y = 5$

(1, 5)

Step 3: Set x to 2

$-2(2) + y = 3$

$-4 + y + 4 = 3 + 4$

$y = 7$

(2, 7)

Step 4: Set x to 3

$-2(3) + y = 3$

$-6 + y + 6 = 3 + 6$

$y = 9$

(3, 9)

4 0

2 years ago

Read 2 more answers

Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P and volume V satisfy the eq

lawyer [7]

Answer:

The value of rate of decrease of volume = - 3600 $\frac{k pa}{min}$

Step-by-step explanation:

According to Boyle's law P V = C ------- (1)

Pressure ( P ) = 100 k pa = 10 $\frac{N}{cm^{2} }$

Volume ( V ) = 900 $cm^{3}$

Put these values in equation ( 1 ) we get,

⇒ C = 10 × 900 = 9000 N-cm = 90 N-m

Differentiate Equation ( 1 ) with respect to time we get,

⇒ V $\frac{dP}{dt}$ + P $\frac{dV}{dt}$ = 0

⇒ V $\frac{dP}{dt}$ = - P $\frac{dV}{dt}$

⇒ $\frac{dV}{dt}$ = - $\frac{V}{P}$ $\frac{dP}{dt}$ ---------- (2)

This equation gives the rate of decrease of volume.

Given that Rate of increase of pressure = $\frac{dP}{dt}$ = 40 $\frac{k pa}{min}$

C = 90 N-m

P = $10^{5}$ pa = 10 $\frac{N}{cm^{2} }$

V = 900 $cm^{3}$

Put all the above values in equation 2 we get,

⇒ $\frac{dV}{dt}$ = - $\frac{900}{10}$ × 40

⇒ $\frac{dV}{dt}$ = - 3600 $\frac{k pa}{min}$

This is the value of rate of decrease of volume.

8 0

3 years ago

7 x [(7+7) divided 7] =

galben [10]

BIDMAS

Step-by-step explanation:

FIRST DO 7+7÷7 AND TIMES THE ANSWER BY 7

6 0

3 years ago

Read 2 more answers

Cos 0=9/15 find tan 0

Liula [17]

Answer:

I HAVE NO CLUE BUT HAVE A NICE DAY....

5 0

2 years ago

In a sample of 1000 randomly selected consumers who had opportunities to send in a rebate claim form after purchasing a product,

Vadim26 [7]

Answer: 0.2872

Step-by-step explanation:

Given : In a sample of 1000 randomly selected consumers who had opportunities to send in a rebate claim form after purchasing a product, 260 of these people said they never did so.

i.e. n= 1000 and x= 260

⇒ Sample proportion : $\hat{p}=\dfrac{260}{1000}=0.26$

z-value for 95% confidence interval : $z_c=1.960$

Now, an upper confidence bound at the 95% confidence level for the true proportion of such consumers who never apply for a rebate. :-

$\hat{p}+ z_c\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$=0.26+ (1.96)\sqrt{\dfrac{0.26(1-0.26)}{1000}}$

$=0.26+ (1.96)(0.01387)=0.26+0.0271852=0.2871852\approx0.2872$

∴ An upper confidence bound at the 95% confidence level for the true proportion of such consumers who never apply for a rebate : 0.2872

7 0

3 years ago