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ExtremeBDS [4]
3 years ago
11

A rectangular garden has dimensions of 100 feet by 10 feet. Next season, the garden is decreased to 2/5 of its size. What is the

scale of the drawing for the new garden shown below?

Mathematics
1 answer:
vladimir1956 [14]3 years ago
7 0
The answer will be 40 feet because w = 10 feet’s so it will decrease into 100
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12.33 to the nearest tenth
ivann1987 [24]
12.3 is the answer i think 
7 0
3 years ago
Read 2 more answers
A company find that 4 1/4 % of the tyres are defective. The company made 28,000 tyres. How many tyres were defective?
Bumek [7]

Answer:

595 pairs of tyres are defective.

Step-by-step explanation:

4.25×28000

____

100

0.0425×28000

1190 Total no. of defective tyres

1190 divide total tyres by 2 to get the exact pairs of defective tyres.

____

  2  

595 tyresof shoes are defective.

3 0
3 years ago
ROOTS AND CUBES<br> Can someone please help me answer all 4 following?
Alex Ar [27]

NOTES:

  • squared (²) means multiply that number by itself 2 times
  • cubed (³) means multiply that number by itself 3 times
  • square root (√) means 2 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical
  • cubed root (∛) means 3 numbers multiplied by itself on the inside simplify to 1 of that number on the outside of the radical

Answer: (C) 41

<u>Step-by-step explanation:</u>

\quad 6^2+\sqrt[3]{125} \\= 6 \cdot 6+\sqrt[3]{5\cdot 5 \cdot 5}\\= 36 + 5\\= 41

***************************************************************************************

Answer: (C) 10

<u>Step-by-step explanation:</u>

   \bigg(\dfrac{7}{3}\times \sqrt[3]{27}-2\bigg)\times \dfrac{1}{5} + \sqrt{81}

=\bigg(\dfrac{7}{3}\times \sqrt[3]{3\cdot 3 \cdot 3}-2\bigg)\times \dfrac{1}{5} + \sqrt{9\cdot 9}

=\bigg(\dfrac{7}{3}\times3-2\bigg)\times \dfrac{1}{5}+9

=(7 - 2)\times \dfrac{1}{5}+9

=5 \times \dfrac{1}{5}+ 9

= 1 + 9

= 10

***************************************************************************************

8² = 8 · 8 = 64                                     11² = 11 · 11 = 121

5³ = 5 · 5 · 5 = 125                               3³ = 3 · 3 · 3 = 27

\sqrt{1600}=\sqrt{40\cdot 40}=40                       \sqrt[3]{64}=\sqrt[3]{4\cdot 4\cdot 4}=4

\sqrt{144}=\sqrt{12\cdot 12}=12                            \sqrt[3]{8000}=\sqrt[3]{20\cdot 20\cdot 20}=20

3 0
3 years ago
Use synthetic substitution to find f (-5) for f (x) = x3 – 5x +2.
Sonbull [250]

Answer:

_5(_5)=25

25+2=27

3(_5)=_15

27_15=12

8 0
3 years ago
Read 2 more answers
A cylindrical container has a radius of 3 centimeters and a height of 12 centimeters. The container is filled with water up to t
evablogger [386]

Answer:

volume of empty space = 141.3 cm³

Step-by-step explanation:

volume of empty space = volume of the cylinder - volume of water

First, we need to calculate the volume of the container

volume of a cylinder = πr²h

 where r = radius of the container   and   h is the height of the container

r = 3cm  and h = 12 cm    π is a constant which is ≈ 3.14

volume of a cylinder = πr²h

                                  =3.14 × 3²×12

                                   =3.14×9×12

                                    =339.12 cm³

We will proceed to find the volume of water

since liquid will take the shape of its container,

then volume of water =  πr²h

r is the radius of the container   and    h is the height of the water

r = 3cm    and   h = 7cm      

volume of water =  πr²h

                             = 3.14 ×3²×7

                              =3.14×9×7

                              =197.82 cm³

volume of empty space = volume of the cylinder - volume of water

                                          =339.12 cm³    -    197.82 cm³

                                          = 141.3 cm³

OR

WE CAN SOLVE DIRECTLY

height of empty space = height of container - height of water

                                       = 12 - 7

                                        =5 cm

volume of empty space = πr²h

                                        =3.14×3²×5

                                        =3.14×9×5

                                         =141.3 cm³

volume of empty space = 141.3 cm³

4 0
3 years ago
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