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3 years ago

Ok so I need to evaluate three questions without a calculator

Mathematics

1 answer:

ki77a [65]3 years ago

6 0

Step-by-step explanation:

log2 32= log32/log2= log 2^5/log2=5log2/log2=5 (log2=0.3)

log7 1= log1/log7= 0 (log1=0)

log5 625= log625/log5= log5^4/log5= 4log5/log5= 4 (log5=0.69)

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Two points (-2,4) and (2,4) and plotted on a coordinate grid. Which expression below can you use to find the distance between tw

Allushta [10]

Answer:

First, let's address the general case.

When we have two points (a,b) and (c,d)

The distance between those points can be written as:

D = √( (a - c)^2 + (b - d)^2)

In this case, the points are:

(-2,4) and (2,4)

Then the distance is:

D = √( (-2 - 2)^2 + (4 - 4)^2) = √(-4)^2 = 4.

The equivalent expression to this is: |-2| + |2|

because:

I-2I = 2

I2I = 2

I-2I + I2I = 2 + 2 = 4.

8 0

3 years ago

Find the surface area of the figure. 13.5 m m 2 9 m 9 m

kvasek [131]

Answer and Step-by-step explanation:

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4 0

3 years ago

What is 1+2+3+54+89+34=

Dmitriy789 [7]

Answer:

183

Step-by-step explanation:

i hope it's helpful for you

5 0

3 years ago

Read 2 more answers

Which of the following equations would not be a line when graphed? Explain how you can tell by just looking at the equations.

zlopas [31]

Y=2/x. this equation has degree -1 whereas linear functions have degree 1

y=6x²-7 is nonlinear as it is degree 2

5 0

3 years ago

Read 2 more answers

What equation represents the line that is perpendicular to y=1/2x - 3 and passes through the point (4,-6)?

zmey [24]

Answer:

The equation of line perpendicular to given line and passing through point (4 , - 6) is y = - 2 x - 2

Step-by-step explanation:

Given as :

The equation of line is

y = $\dfrac{1}{2}$ x - 3

Now, standard equation of line is

y = m x + c

where m is the slope of line and c is the y-intercept

So, comparing with standard line equation with given line equation

∴ slope of given line = m = $\dfrac{1}{2}$

Again

other line is perpendicular to given line and passes through point (4 , - 6)

Let The slope of other line = M

∵ Two lines are perpendicular

∴ From perpendicular lines property , the product of lines = - 1

i.e m × M = -1

Or, $\dfrac{1}{2}$ × M = -1

Or M = $\frac{-1}{\frac{1}{2}}$

∴ M = - 2

So, The slope of other line = M = - 2

Now, equation of line with slope - 2 and points (4 , - 6) in slope-point form

y - $y_1$ = M (x - $x_1$ )

Or, y - ( - 6) = ( -2) × (x - 4)

Or, y + 6 = - 2 x + 4

Or, y = - 2 x + 4 - 6

∴ y = - 2 x - 2

So, The equation of other line is y = - 2 x - 2

Hence, The equation of line perpendicular to given line and passing through point (4 , - 6) is y = - 2 x - 2 Answer

5 0

3 years ago