Question

A child riding a bicycle at 15 m/s accelerates at 3. 0 m/s/s for 4. 0 s. What is the child's speed at the end of this 4. 0 s interval?.

Answer 1

Answer:

The final speed of bicycle would be 27 m/s².

Step-by-step explanation:

Given :

• $\small\red\bull$ Initial velocity (u) = 15 m/s
• $\small\red\bull$ Acceleration (a) = 3.0 m/s²
• $\small\red\bull$ Time = 4 seconds

To Find :

• $\small\red\bull$ Final velocity (v)

Using Formula :

$\longrightarrow{\pmb{\sf{v = u + at}}}$

• $\small\blue\star$ v = final velocity
• $\small\blue\star$ u = initial velocity
• $\small\blue\star$ a = acceleration
• $\small\blue\star$ t = time taken

Solution :

Substituting the values in the formula to find the final velocity :

$\longrightarrow{\sf{v = u + at}}$

$\longrightarrow{\sf{v = 15 + (3.0 \times 4)}}$

$\longrightarrow{\sf{v = 15 + (3 \times 4)}}$

$\longrightarrow{\sf{v = 15 +(12)}}$

$\longrightarrow{\sf{v = 15 +12}}$

$\longrightarrow{\sf{v = 27 \: {m/s}^{2}}}$

$\star{\underline{\boxed{\red{\sf{v = 27 \: {m/s}^{2}}}}}}$

Hence, the final speed of bicycle would be 27 m/s².

$\rule{300}{1.5}$