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2 years ago

Can I get some help with these questions?

Mathematics

1 answer:

juin [17]2 years ago

6 0

Answer:

For the first question its X=110 For the second question angle AEF is 75 degrees and for angle ADF is 105 degrees

Step-by-step explanation:

the total angle is 150 so take 4+22 and you get 26 then add 6+8 and you get 14 add 26+14 and you get 40 do 150-40 and you get 110 therefore x=110

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A number is divided in the ratio 3:4. If the first part is 24, find the number.

dedylja [7]

Answer:

Step-by-step explanation:

<h3>Let the other part be x.</h3>

<h3>Other part = 32</h3>

<h2>mark me brainlist!</h2>

5 0

2 years ago

Can someone solve this

zysi [14]

You know how Soh Cah Toa applies to right triangles; you can assign the adjacent side = 4 and hypotenuse = 7

CosФ = (adjacent) / (hypotenuse)

Then with the Pythagorean theorem
4² + b² = 7²
16 + b² = 49
b² = 49 - 16
b² = 33
b = √(33)

So "b" is the opposite side.

SinФ = (opposite) / (hypotenuse) = √(33)/7
TanФ = (opposite) / (adjacent) = √(33)/4

3 0

3 years ago

What decimal part of 80 is 90

Elodia [21]

88.89% of 90 would be 80

6 0

3 years ago

Complete the identity

spin [16.1K]

Answer: $cos(\pi-x)=-cos(x)$

Step-by-step explanation:

We need to apply the following identity:

$cos(A - B) = cos A*cos B + sinA*sin B$

Then, applying this, you know that for $cos(\pi-x)$ :

$cos(\pi-x)=cos(\pi)*cos(x)+sin(\pi)*sin(x)$

We need to remember that:

$cos(\pi)=-1$ and $sin(\pi)=0$

Therefore, we need to substitute these values into $cos(\pi-x)=cos(\pi)*cos(x)+sin(\pi)*sin(x)$ .

Then, you get:

$cos(\pi-x)=(-1)*cos(x)+0*sin(x)$

$cos(\pi-x)=-1cos(x)+0$

$cos(\pi-x)=-cos(x)$

8 0

3 years ago

Find the inverse y=3x+2

Gwar [14]

$y=3x+2\\\\\text{replace x with y and y with x}\\\\3y+2=x\\\\\text{solve for y}\\\\3y+2=x\ \ \ \ \ |-2\\\\3y=x-2\ \ \ \ \ |:3\\\\\boxed{y=\dfrac{x-2}{3}}$

4 0

3 years ago

Can I get some help with these questions?​

Can I get some help with these questions?