Answer:
1. b ∈ B 2. ∀ a ∈ N; 2a ∈ Z 3. N ⊂ Z ⊂ Q ⊂ R 4. J ≤ J⁻¹ : J ∈ Z⁻
Step-by-step explanation:
1. Let b be the number and B be the set, so mathematically, it is written as
b ∈ B.
2. Let a be an element of natural number N and 2a be an even number. Since 2a is in the set of integers Z, we write
∀ a ∈ N; 2a ∈ Z
3. Let N represent the set of natural numbers, Z represent the set of integers, Q represent the set of rational numbers, and R represent the set of rational numbers.
Since each set is a subset of the latter set, we write
N ⊂ Z ⊂ Q ⊂ R .
4. Let J be the negative integer which is an element if negative integers. Let the set of negative integers be represented by Z⁻. Since J is less than or equal to its inverse, we write
J ≤ J⁻¹ : J ∈ Z⁻
A. Your not multiplying 8 by anything to get this answer your taking 8-14-a
Line plots are like for rounding them or put them in order fracton
Answer:
the probability that a student takes theater given that the student is taking choir is 0.3
Step-by-step explanation:
The probability that a student takes theater and choir = 0.078
The probability that a student takes choir = 0.26
the probability that a student takes theater given that the student is taking choir ?
We can solve this using conditional probability.
P(B|A) = P(A and B)/P(A)
In our case the conditional probability will be:
P(Theater | Choir) = P(Choir and Theater)/ P(Choir)
Putting the given values
P(Theater | Choir) = (0.078) / 0.26
P(Theater | Choir) = 0.3
So, the probability that a student takes theater given that the student is taking choir is 0.3
