Answer:75
Step-by-step explanation:
Area of triangle:
A= 1/2*b*h
= 1/2 *(29)* (19)
= 1/2 *(551)
= <u>275.5 in^2</u>
Area of rectangle:
A= l * w
= (29) * (10)
= <u>290 in^2</u>
Total Area:
275.5 + 290 = <u>565.5 in^2</u>
Hope this helps! Have a great day :)
Answer: ![-3\sqrt{5}](https://tex.z-dn.net/?f=-3%5Csqrt%7B5%7D)
-3 times the square root of 5
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Explanation:
Let ![x = \sqrt{5}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%7B5%7D)
Replace all the root 5 terms with x and we go from
![3\sqrt{5}-8\sqrt{5}+2\sqrt{5}](https://tex.z-dn.net/?f=3%5Csqrt%7B5%7D-8%5Csqrt%7B5%7D%2B2%5Csqrt%7B5%7D)
to
![3x-8x+2x](https://tex.z-dn.net/?f=3x-8x%2B2x)
From here, combine like terms to get
![3x-8x+2x = -5x+2x = -3x](https://tex.z-dn.net/?f=3x-8x%2B2x%20%3D%20-5x%2B2x%20%3D%20-3x)
and the last thing to do is replace the x with sqrt(5)
![-3x = -3\sqrt{5}](https://tex.z-dn.net/?f=-3x%20%3D%20-3%5Csqrt%7B5%7D)
Meaning that,
![3x-8x+2x = -3x](https://tex.z-dn.net/?f=3x-8x%2B2x%20%3D%20-3x)
![3\sqrt{5}-8\sqrt{5}+2\sqrt{5} = -3\sqrt{5}](https://tex.z-dn.net/?f=3%5Csqrt%7B5%7D-8%5Csqrt%7B5%7D%2B2%5Csqrt%7B5%7D%20%3D%20-3%5Csqrt%7B5%7D)
The answer is C because the equations become true.