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2 years ago

Ayudaaa necesito resolver 2 ejercicios A) √x+2=x B) 3+√2x-6=x

Mathematics

2 answers:

ANTONII [103]2 years ago

7 0

A is 4 but I’m not sure about b

mojhsa [17]2 years ago

5 0

Answer:

A) x=4

B)x= $\sqrt{2}$ +3 or 7.24

Step-by-step explanation:

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What is the circumference of a circle with a diameter of 20 inches

sergeinik [125]

Answer:

62.8 in

Step-by-step explanation:

Circumfrence=pi x diameter

3.14 x 20=62.8

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3 years ago

What is 27ac-9abc+15acf

Oliga [24]

3ac(9-3b+5f) you got to do factorization

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3 years ago

Describe the relationship between the number of "at bats" and the number of hits using the data in the scatter plot.

butalik [34]

Answer: A.) For these data, as the number of at bats increases, the number of hits tend to increase.

This is because the points seem to trend upward as we move from left to right. This makes sense because the more attempts you get, the more hits you're expected to get.

Assume that someone has a batting average of 0.300; this means that if they got 1000 attempts, then we expect about 0.300*1000 = 300 hits. Now if they got 2000 at bats this time, then we expect about 0.300*2000 = 600 hits.

Of course things won't fit this perfectly since everything in life has random statistical error, but this gives a good idea of the upward trending data. The two variables (at bats and hits) are strongly related. We can say the variables have strong positive correlation.

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2 years ago

Assume that the helium porosity of coal samples taken from any particular seam is Normally distributed with true standard deviat

riadik2000 [5.3K]

Answer:

a) $4.85-2.33\frac{0.75}{\sqrt{20}}=4.46$

$4.85+2.33\frac{0.75}{\sqrt{20}}=5.24$

b) $4.56-2.33\frac{0.75}{\sqrt{16}}=4.12$

$4.56+2.33\frac{0.75}{\sqrt{16}}=4.99$

c) $n=(\frac{1.960(0.75)}{0.2})^2 =54.02 \approx 55$

Step-by-step explanation:

Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.01,0,1)".And we see that $z_{\alpha/2}=2.33$

Now we have everything in order to replace into formula (1):

$4.85-2.33\frac{0.75}{\sqrt{20}}=4.46$

$4.85+2.33\frac{0.75}{\sqrt{20}}=5.24$

Part b

$4.56-2.33\frac{0.75}{\sqrt{16}}=4.12$

$4.56+2.33\frac{0.75}{\sqrt{16}}=4.99$

Part c

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =0.4/2 =0.2 we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got $z_{\alpha/2}=1.960$ , replacing into formula (b) we got:

$n=(\frac{1.960(0.75)}{0.2})^2 =54.02 \approx 55$

5 0

3 years ago

YALL WHAT IS THE ANGLE OF C <br> 65<br> 65

SSSSS [86.1K]

Answer:

A,G

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers