Q1)
is the function representing the weekly paycheck of salesman A a proportional relationship?
p - function
s - number of sales
Salesman A earns £65 per sale. Therefore if he earns s number of sales, the total amount he earns is 65*s = 65s
Lets assume for s number of sales he receives his maximum weekly commission, therefore the equation for A's weekly payment is;
p = 65s +1300
to determine if p and s are proportional to each other, it should take the form of equation p=ks
where k is a constant. If we graph p=ks, then k is the slope that is a constant and the line should pass through the origin, which means that y intercept is 0.
however in this equation there is an intercept of +1300, therefore p and s are not proportional values.
Q2)
For salesman B he has a weekly base salary of £300 and commission of £40 per sale. Then the salary is fixed however for s number of sales, the commission he will receive is 40*s = 40s
the function for B's payment is as follows;
p = 40s + 300
This equation if we take it as a graph equation with p and s as y and x coordinates respectively, the equation we get is of one with an intercept of +300
therefore if we graph it, the line will not pass through the origin which means that the p and s values are not proportional to each other.
Q3)
Salesman C receives a weekly salary of £900. This is a fixed amount and does not vary depending on the sales. Therefore this is anyway not proportional as p function is not affected by s value.
therefore p and s are not related, hence they aren't proportional.
p = 900
That’s the 90 degree angle right
Answer:
b. 225 joules
Step-by-step explanation:
plug in 5 m/s and 12.5 m/s in to v and h.
Answer:
(i) 7/10
(ii) 3/10
(iii) 1/5
(iv) Rs 40,000
Step-by-step explanation:
The fraction of the salary spent on food = 1/2
The fraction of the salary spent on rented house fee = 1/5
(i) The fraction spent for both food and rental fee = (1/2) + (1/5) = (5 + 2)/10 = 7/10
(ii) The remainder (rest) of the salary = 1 - 7/10 = 3/10
The fraction of the remainder spent for children's education = 1/3
The fraction of the total salary spent for the children's education = (1/3) × (3/10) = 1/10
(iii) The remaining portion deposited in the bank = 1 - (1/10 + 7/10)) = 2/10 = 1/5
(iv) The amount equal to portion of 1/5 of his salary deposited in the bank is Rs 8000
Let <em>x</em> represent his whole salary, we have;
(1/5) × x = Rs 8,000
x = 5 × Rs 8,000 = Rs 40,000
His whole salary is Rs 40,000.
